/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 Describe how to find the inverse... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Describe how to find the inverse of a one-to-one function.

Short Answer

Expert verified
To find the inverse of a one-to-one function, replace the function with \(y\), swap \(x\) and \(y\), and then solve for \(y\).

Step by step solution

01

Definition of One-to-One Function

A one-to-one function, also called an injective function, is a function where every element of the range corresponds with one and only one element of the domain.
02

Definition of Inverse Function

The inverse of a function flips the function around the line \(y = x\), so the output values of the function become the input values of the inverse and vice versa. The inverse function of \(f\) is often denoted as \(f^{-1}\).
03

Procedure to Find Inverse Function

To find the inverse of a one-to-one function, first replace the function name with \(y\). Then switch the roles of \(y\) and \(x\); that is, swap the positions of \(y\) and \(x\) in the equation. After, solve the equation for \(y\) to get the inverse function.
04

Example

For example, take the one-to-one function \(f(x) = 3x+2\). Replace \(f(x)\) with \(y\) to give the equation \(y = 3x + 2\). Swap \(x\) and \(y\) to get \(x = 3y + 2\). Finally, solve for \(y\) to get \(y = (x - 2) / 3\), which is the inverse function \(f^{-1}(x) = (x - 2) / 3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.