Chapter 12: Problem 9
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$32^{x}=8$$
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 12: Problem 9
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$32^{x}=8$$
All the tools & learning materials you need for study success - in one app.
Get started for free
Solve: $$\sqrt{2 x-1}-\sqrt{x-1}=1$$
a. Simplify: \(e^{\ln 3}\) b. Use your simplification from part (a) to rewrite \(3^{x}\) in terms of base \(e\)
Explain how to use your calculator to find \(\log _{14} 283\)
Complete the table for a savings account subject to n compounding periods per year \(\left[A=P\left(1+\frac{r}{n}\right)^{n t}\right]\) Round answers to one decimal place. $$\begin{array}{l|c|l|l|l} \hline \begin{array}{l} \text { Amount } \\ \text { Invested } \end{array} & \begin{array}{l} \text { Number of } \\ \text { Compounding } \\ \text { Periods } \end{array} & \begin{array}{l} \text { Annual Interest } \\ \text { Rate } \end{array} & \begin{array}{l} \text { Accumulated } \\ \text { Amount } \end{array} & \begin{array}{l} \text { Time } t \\ \text { in Years } \end{array} \\ \hline \$ 1000 & 360 & & \$ 1400 & 2 \\ \hline \end{array}$$
You overhear a student talking about a property of logarithms in which division becomes subtraction. Explain what the student means by this.
What do you think about this solution?
We value your feedback to improve our textbook solutions.