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Given below are the sodium contents (in mg) for seven brands of hot dogs rated as "very good" by Consumer Reports (www.consumerreports.org): $$\begin{array}{lllllll} 420 & 470 & 350 & 360 & 270 & 550 & 530 \end{array}$$ a. Use the given data to produce a point estimate of \(\mu\), the true mean sodium content for hot dogs. b. Use the given data to produce a point estimate of \(\sigma^{2}\), the variance of sodium content for hot dogs. c. Use the given data to produce an estimate of \(\sigma\), the standard deviation of sodium content. Is the statistic you used to produce your estimate unbiased?

Short Answer

Expert verified
The mean sodium content is 420 mg, the variance is 10286 mg^2, and the standard deviation is approximately 101.42 mg. The estimator used for the standard deviation is biased.

Step by step solution

01

Estimate the mean

The mean, or average, is given by the sum of all values divided by the number of values. Symbolically, for our set of data \(x_1, x_2, ..., x_n\), this is done by calculating \(\mu = (x_1 + x_2 + ... + x_n) / n\). For the given sodium content values, the mean is then \(\mu = (420 + 470 + 350 + 360 + 270 + 550 + 530) / 7 = 420 mg\).
02

Calculate the variance

Variance is calculated by finding the average of the squared differences from the Mean. For the given data, the formula is \(\sigma^2 = ((x_1 - \mu)^2 + (x_2 - \mu)^2 + ... +(x_n - \mu)^2) / n \). Substituting the data yields the variance \(\sigma^2 = ((420 - 420)^2 + (470 - 420)^2 + (350 - 420)^2 + (360 - 420)^2 + (270 - 420)^2 + (550 - 420)^2 + (530 - 420)^2) / 7 = 10286 mg^2\).
03

Estimate standard deviation and check if the statistic is unbiased

The standard deviation is given by the square root of the variance, so \(\sigma = \sqrt{\sigma^2}\). This gives us \(\sigma = \sqrt{10286} = 101.42 mg\). As for the question of bias, our estimator for standard deviation is not unbiased. A good rule of thumb is that in variance and standard deviation calculations, we would divide by \((n - 1)\) instead of \(n\) to get an unbiased estimator, but here we’ve divided by \(n\), so it's a biased estimator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point Estimate
The term point estimate refers to a single value that serves as an approximation of an unknown population parameter. It’s like taking a snapshot to infer the big picture from a sample. In statistics, the most common type of point estimate is the mean or average of the data set.

For the sodium content in hot dogs example, we calculate the average sodium content to represent the whole market of 'very good' hot dogs. By summing all the given sodium contents and dividing by the number of hot dogs, we obtain a point estimate of the true mean, \(\mu\), of the population. Here, the point estimate is that the average sodium content of 'very good' hot dogs is 420 mg. This figure was arrived at by adding together all the individual sodium contents and dividing by seven, the total number of hot dog brands sampled.
Mean Calculation
Calculating the mean is a fundamental process in statistics. It’s the arithmetic average and gives us a central value of a data set. To calculate the mean, we sum up all values and then divide by the total number of values in the set.

Let’s walk through an example: if we wanted to find the mean amount of sodium in hot dogs, we would add up the sodium contents of all the hot dogs in our sample (in mg) and divide by the number of hot dogs. Using the provided data, the calculation would be \(\mu = \frac{420 + 470 + 350 + 360 + 270 + 550 + 530}{7} = 420 mg\). So, the mean sodium content of the seven 'very good' hot dog brands sampled is 420 mg.
Variance
When we talk about variance in statistics, we’re looking at a measure of how broadly numbers in a set are spread out from their mean. It reflects the degree of variation within the data set. If all numbers are close to the mean, variance is low; if they are spread out, variance is high.

Formula for Variance

The formula is \(\sigma^2 = \frac{(x_1 - \mu)^2 + (x_2 - \mu)^2 + ... +(x_n - \mu)^2}{n}\), where each \(x_i\) is a value from the data set, \(\mu\) is the mean, and \(n\) is the number of data points.

For our hot dog example, after computing the mean as 420 mg, we use the formula to calculate variance. The squared differences between each sodium content and the mean are averaged, leading to a variance of 10286 \(mg^2\). This high variance indicates a substantial spread in the sodium contents of the hot dogs examined.
Standard Deviation
The standard deviation is the square root of variance and provides a clear idea of how much individual data points deviate from the mean on average. It is expressed in the same units as the data, making it more interpretable than variance.

Unbiased Estimator

When using sample data to estimate the standard deviation of a population, an unbiased estimator is preferred. The sample standard deviation is commonly calculated by dividing the sum of squared deviations by \(n - 1\) instead of \(n\), accounting for the degrees of freedom lost during estimation. This adjustment makes it an unbiased estimator.

In our sodium content case, the standard deviation is approximated by \(\sigma = \sqrt{10286} = 101.42 mg\). However, since this estimate was derived by dividing the sum of squared deviations by \(n\) rather than \(n - 1\), it is a biased estimator. In summary, while the standard deviation gives us a useful measure of spread, the method used here underestimates the variability expected if we obtained the entire population’s data.

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Most popular questions from this chapter

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