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The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that \(37 \%\) of college freshmen and \(48 \%\) of college seniors carry a credit card balance from month to month. Suppose that the reported percentages were based on random samples of 1000 college freshmen and 1000 college seniors. a. Construct a \(90 \%\) confidence interval for the proportion of college freshmen who carry a credit card balance from month to month. b. Construct a \(90 \%\) confidence interval for the proportion of college seniors who carry a credit card balance from month to month. c. Explain why the two \(90 \%\) confidence intervals from Parts (a) and (b) are not the same width.

Short Answer

Expert verified
The 90% confidence interval for the proportion of freshmen who carry a balance is (0.340 , 0.400). The 90% confidence interval for the proportion of seniors who carry a balance is (0.449 , 0.511). The difference in the widths of these intervals is due to the different proportions, which resulted in different standard errors.

Step by step solution

01

Construct Confidence Interval for Freshmen

The first step is to construct a 90% confidence interval for the proportion of college freshmen who carry a credit card balance from month to month. Based on the sample size of 1000, and a result of 37%, the calculation for the standard error would first need to be calculated as follows: \(\sqrt{ (0.37 * (1-0.37)) / 1000} = 0.0152\). This can then be used to calculate the confidence interval using the formula \(p \pm z*\sqrt{ (p*(1-p)/n }\). With the Z-score for a 90% confidence interval being 1.645, the calculation for the confidence interval can be done as follows: \((0.37 - 1.645*0.0152 , 0.37 + 1.645*0.0152)\).
02

Construct Confidence Interval for Seniors

The second step is to construct a 90% confidence interval for the proportion of college seniors who carry a credit card balance from month to month. As with the previous step, the calculation of the standard error needs to be done first as follows: \(\sqrt{ (0.48 * (1-0.48)) / 1000} = 0.0157\). The calculation for the confidence interval can then be done as follows: \((0.48 - 1.645*0.0157 , 0.48 + 1.645*0.0157)\).
03

Explaining the Difference

The third and final step is to explain why the widths of the two confidence intervals are different. The width of a confidence interval is determined by the standard error and the Z-score. In this case, both intervals have the same level of confidence and thus the same Z-score of 1.645. Therefore, the difference in the widths must be due to the difference in the standard error, which is influenced by the sample proportion. Since the proportions (.37 for freshmen and .48 for seniors) are different, this leads to different standard errors, and hence different interval widths.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
In statistics, a **proportion** is a way of measuring a part of a whole. It is calculated by dividing the number of successes or desired outcomes by the total number in the sample. For example, in our exercise, the reported results of 37% for college freshmen and 48% for college seniors represent the proportions of those carrying a credit card balance each month. These proportions are important because they give us an estimative snapshot of the entire population based on the data gathered from a sample.

Key aspects of a proportion include:
  • It is expressed as a percentage, fraction, or decimal.
  • It helps in making inferences about a population from a sample.
  • The sample proportion will be used to compute the confidence interval.
Understanding proportions allows us to estimate population parameters effectively, especially when it is too expensive or impractical to gather full population data.
Standard Error
The **standard error** is a crucial statistical concept that helps us understand the variability of a sample proportion. It measures how much the proportion of the sample might vary from the actual population proportion if you were to repeat your sample many times. Calculating the standard error is essential in constructing confidence intervals, such as those for proportions of freshmen and seniors carrying a credit card balance.

The formula for standard error of a proportion is:\[SE = \sqrt{ \frac{p(1-p)}{n} }\]
Where:
  • \( p \) is the sample proportion.
  • \( n \) is the sample size.
A smaller standard error indicates that the sample proportion is close to the population proportion, which results in a narrower confidence interval. In our exercise, this was evident as different proportions resulted in slightly different standard errors, thus affecting the width of confidence intervals.
Z-score
The **Z-score** is a dimensionless statistic that tells us how many standard deviations our data is from the mean in a standard normal distribution. In the context of confidence intervals, the Z-score provides a measure of confidence in our results. For a 90% confidence interval, the Z-score typically used is approximately 1.645. This value is derived from the properties of the standard normal distribution and corresponds to the desired confidence level.

Key points about the Z-score:
  • It demonstrates the number of standard errors a point is away from the mean.
  • A Z-score value is consistent for a given confidence level.
  • For our exercise, both the confidence intervals for the freshmen and seniors used a Z-score of 1.645.
The Z-score is critical for determining the margin of error in confidence intervals. It helps us understand the degree of certainty regarding how representative our sample statistics are for the entire population.
Sample Size
**Sample size** is a key component in statistical analysis and directly affects the accuracy of results. In the context of confidence intervals, a larger sample size tends to give more reliable estimates of population parameters. For the given exercise, the sample sizes for both freshmen and seniors are 1000, which is considered a substantial number for statistical purposes.

The influence of sample size includes:
  • With a larger sample size, the standard error tends to decrease, leading to a narrower confidence interval.
  • Higher sample sizes generally provide better approximation of the population parameter.
  • It influences the precision of the estimated proportion as seen with both freshmen and seniors.
Understanding sample size is important because it is a factor that can often be controlled in studies to optimize the accuracy and reliability of statistical estimates like confidence intervals.

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Most popular questions from this chapter

How much money do people spend on graduation gifts? In 2007, the National Retail Federation (www.nrf.com) surveyed 2815 consumers who reported that they bought one or more graduation gifts that year. The sample was selected in a way designed to produce a sample representative of adult Americans who purchased graduation gifts in \(2007 .\) For this sample, the mean amount spent per gift was \(\$ 55.05 .\) Suppose that the sample standard deviation was \(\$ 20 .\) Construct and interpret a \(98 \%\) confidence interval for the mean amount of money spent per graduation gift in 2007 .

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The Associated Press (December 16,1991 ) reported that in a random sample of 507 people, only 142 correctly described the Bill of Rights as the first 10 amendments to the U.S. Constitution. Calculate a \(95 \%\) confidence interval for the proportion of the entire population that could give a correct description.

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