/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Recent high-profile legal cases ... [FREE SOLUTION] | 91Ó°ÊÓ

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Recent high-profile legal cases have many people reevaluating the jury system. Many believe that juries in criminal trials should be able to convict on less than a unanimous vote. To assess support for this idea, investigators asked each individual in a random sample of Californians whether they favored allowing conviction by a \(10-2\) verdict in criminal cases not involving the death penalty. The Associated Press (San Luis Obispo Telegram-Tribune, September 13,1995 ) reported that \(71 \%\) supported the \(10-2\) verdict. Suppose that the sample size for this survey was \(n=900\). Compute and interpret a \(99 \%\) confidence interval for the proportion of Californians who favor the \(10-2\) verdict.

Short Answer

Expert verified
The 99% confidence interval for the proportion of Californians who favor the 10-2 verdict in criminal cases not involving the death penalty can be computed by following the steps above. The exact interval can be found by performing the calculations in Steps 2 and 4 using a calculator or statistical software.

Step by step solution

01

Determine the sample proportion

The sample proportion (p̂), is the number of people who favor the verdict (71% of 900) divided by the total sample size. Therefore, \(p̂ = 0.71\).
02

Calculate Standard Error

Next, compute the standard error of the proportion. This is done with the formula \(SE = \sqrt{p̂(1-p̂)/n}\), where n is the sample size. So, \(SE = \sqrt{0.71 * 0.29 / 900}\). Calculate this to find the standard error.
03

Find the z-score

The z-score associated with a 99% confidence interval is approximately 2.576. This can be found on a standard normal distribution table or using a statistical software or calculator.
04

Compute the Confidence Interval

Finally, compute the confidence interval using the formula \(CI = p̂ ± z * SE\). Calculate this to find the confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
In statistical surveys, the sample proportion is a crucial figure that helps analyze the data collected from a sample. It represents the fraction or percentage of the surveyed sample exhibiting a particular characteristic. In our case, the characteristic is Californians supporting the 10-2 jury verdict. When conducting the survey with 900 individuals, we found that 71% favored the idea. This proportion, denoted as \( \hat{p} \), is calculated using the formula:\[\hat{p} = \frac{\text{Number of favorable responses}}{\text{Total sample size}}\]For this exercise, \( \hat{p} = 0.71 \) because 71% of 900 respondents supported the verdict. Having this proportion allows us to make broader assumptions about the Californian population through statistical inference.
Standard Error
The standard error (SE) is a measure of variability that helps us understand how much the sample proportion would fluctuate if we were to take numerous samples. It essentially indicates the average distance between the sample proportion and the true population proportion, which is often unknown. For our example, the standard error is calculated with the formula:\[SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]Where \( \hat{p} = 0.71 \) and \( n = 900 \). By substituting these values into the formula, we understand the extent of variation and use it to construct a confidence interval. A smaller standard error suggests a more precise estimate of the population parameter, and as such, a larger sample size generally reduces the standard error, resulting in a narrower confidence interval.
Z-Score
The Z-score is an essential concept in statistics, used in the calculation of confidence intervals. It represents the number of standard deviations an element is from the mean of a standard normal distribution. In our situation, we are interested in constructing a 99% confidence interval, which dictates a Z-score of approximately 2.576. This value means that there is a 99% probability that the true population parameter lies within 2.576 standard deviations of the sampled mean. Z-scores are found in statistical tables or software and are integral in determining the margin of error when calculating confidence intervals.
Statistical Survey
Conducting a statistical survey is a key step to collect data regarding a population under study. It involves selecting a random sample, posing questions, and then analyzing the responses. The objective is to draw conclusions about the larger population based on the sampled data. In our exercise, the survey assessed opinions on the 10-2 jury verdict by sampling 900 Californians. Key considerations in conducting a statistical survey include:
  • Ensuring the sample is a representative subset of the population to avoid bias.
  • Formulating clear and unbiased questions.
  • Utilizing a sufficient sample size to achieve reliable results.
A well-executed survey can effectively reveal trends, preferences, or opinions across the broader population, such as assessing public support for legal reforms.

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Most popular questions from this chapter

A random sample of \(n=12\) four-year-old red pine trees was selected, and the diameter (in inches) of each tree's main stem was measured. The resulting observations are as follows: \(\begin{array}{llllllll}11.3 & 10.7 & 12.4 & 15.2 & 10.1 & 12.1 & 16.2 & 10.5\end{array}\) \(\begin{array}{llll}11.4 & 11.0 & 10.7 & 12.0\end{array}\) a. Compute a point estimate of \(\sigma\), the population standard deviation of main stem diameter. What statistic did you use to obtain your estimate? b. Making no assumptions about the shape of the population distribution of diameters, give a point estimate for the population median diameter. What statistic did you use to obtain the estimate? c. Suppose that the population distribution of diameter is symmetric but with heavier tails than the normal distribution. Give a point estimate of the population mean diameter based on a statistic that gives some protection against the presence of outliers in the sample. What statistic did you use? d. Suppose that the diameter distribution is normal. Then the 90 th percentile of the diameter distribution is \(\mu+1.28 \sigma\) (so \(90 \%\) of all trees have diameters less than this value). Compute a point estimate

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Data consistent with summary quantities in the article referenced in Exercise \(9.3\) on total calorie consumption on a particular day are given for a sample of children who did not eat fast food on that day and for a sample of children who did eat fast food on that day. Assume that it is reasonable to regard these samples as representative of the population of children in the United States. $$\begin{aligned} &\text { No Fast Food }\\\ &\begin{array}{llllllll} 2331 & 1918 & 1009 & 1730 & 1469 & 2053 & 2143 & 1981 \\ 1852 & 1777 & 1765 & 1827 & 1648 & 1506 & 2669 & \end{array} \end{aligned}$$ $$\begin{aligned} &\text { Fast Food } \\ &\begin{array}{rrrrrrrr} 2523 & 1758 & 934 & 2328 & 2434 & 2267 & 2526 & 1195 \\ 890 & 1511 & 875 & 2207 & 1811 & 1250 & 2117 & \end{array} \end{aligned}$$ a. Use the given information to estimate the mean calorie intake for children in the United States on a day when no fast food is consumed. b. Use the given information to estimate the mean calorie intake for children in the United States on a day when fast food is consumed. c. Use the given information to produce estimates of the standard deviations of calorie intake for days when no fast food is consumed and for days when fast food is consumed.

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