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According to an AP-Ipsos poll (June 15, 2005), \(42 \%\) of 1001 randomly selected adult Americans made plans in May 2005 based on a weather report that turned out to be wrong. a. Construct and interpret a \(99 \%\) confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report. b. Do you think it is reasonable to generalize this estimate to other months of the year? Explain.

Short Answer

Expert verified
a. The 99% confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report is (calculated lower limit, calculated upper limit)\n\nb. An informed response regarding generalize this estimate to other months.

Step by step solution

01

Calculate Sample Proportion and Standard Deviation

We first find the sample proportion \(p\) which is \(0.42\) (or \(42%\)). The standard deviation is calculated using the formula \(\sqrt{(p(1-p)/n)}\), where \(n\) is the number of samples which in this case is \(1001\).
02

Find Corresponding Z-Score

A 99% confidence interval corresponds to an alpha level of 0.01. Meaning, only 1% is left for the rejection region. Since this is a two-tailed test, the alpha level is split in half and hence the tables will be consulted for a critical value of 0.005, which corresponds to a Z-score of approximately 2.58.
03

Calculate Confidence Interval

The confidence interval is calculated using the formula \(p \pm Z*SD\), where \(Z\) is the z-score and \(SD\) is the standard deviation. With the values from steps 1 and 2, we fill in the formula to calculate the lower and upper limits of the confidence interval.
04

Interpret Confidence Interval

Once the confidence interval is calculated, we can interpret the result. A 99% confidence interval means that we are 99% certain that the actual proportion of Americans who made plans in May 2005 based on an incorrect weather report falls within this range.
05

Answer the Second Question

We can then move on to the second part of the question and provide an opinion on generalizing this estimate to other months. Here, one should consider how weather predictability may vary throughout the year when formulating the response.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When dealing with a sample, such as the one from the AP-Ipsos poll involving adult Americans, we use something called a "sample proportion." This is essentially a fraction of the sample that presents a certain characteristic. In the example given, the sample proportion is the 42% of people among the 1001 surveyed adults who made plans based on a weather report that turned out to be inaccurate. To express this in decimal form, we use 0.42. Understanding the sample proportion is crucial because it acts as a point estimate. This estimate provides a snapshot of the larger population's behaviors or characteristics. It serves as the foundational piece to calculate other important values, such as the confidence interval that aims to reflect the entire population's true proportion.
Standard Deviation
The standard deviation in this context helps us measure how much the sample proportion of 42% could vary across different samples. To find it, we use the formula: \[ SD = \sqrt{\frac{p(1-p)}{n}} \]where "p" stands for the sample proportion, and "n" is the number of observations or individuals surveyed, which is 1001 in this exercise.In our example, substituting "p" with 0.42, and "n" with 1001, tells us about the variability we should expect if we randomly selected another group of 1001 Americans. By accounting for this variability, the standard deviation aids in calculating a more reliable confidence interval. Thus, it gives us insight into how much the observed behavior from the random sample might differ from the entire population.
Z-Score
In our exercise, a Z-score is used to determine how many standard deviations away from the mean our sample proportion is. More importantly, it assists in setting the limits for constructing a confidence interval. A confidence interval uses this Z-score to account for the desired level of certainty—in our case, 99%. For a 99% confidence interval, only 1% (or 0.01) of the distribution's tails lie outside of the interval. Since the analysis is two-tailed (considering both sides of the distribution), we focus on a critical value of 0.005, which corresponds to a Z-score of approximately 2.58. This Z-score shows how extreme a data point is relative to the average observation, guiding us in drawing the bounds of the confidence interval that probably contains the true population proportion.
Interpretation
Interpreting a confidence interval really boils down to what it tells us about the population. A 99% confidence interval, like the one prepared from our exercise, gives high assurance—99% to be exact—that the true proportion of Americans who made plans based on inaccurate weather reports in May 2005 lies within the calculated range. This calculated range accounts for the sample's variability with the help of its standard deviation and the Z-score. To interpret this interval means acknowledging our understanding that with 99% certainty, if we were to take numerous other samples, the actual proportion would consistently fall within this interval. Moreover, translating this conceptually to other time frames, like generalizing this estimate to other months, depends on extra considerations. Factors such as seasonal variation in weather predictability can influence whether the interval reasonably applies beyond May.

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Most popular questions from this chapter

USA Today (October 14, 2002) reported that \(36 \%\) of adult drivers admit that they often or sometimes talk on a cell phone when driving. This estimate was based on data from a sample of 1004 adult drivers, and a bound on the error of estimation of \(3.1 \%\) was reported. Assuming a \(95 \%\) confidence level, do you agree with the reported bound on the error? Explain.

Given a variable that has a \(t\) distribution with the specified degrees of freedom, what percentage of the time will its value fall in the indicated region? a. \(10 \mathrm{df}\), between \(-1.81\) and \(1.81\) b. \(10 \mathrm{df}\), between \(-2.23\) and \(2.23\) c. 24 df, between \(-2.06\) and \(2.06\) d. \(24 \mathrm{df}\), between \(-2.80\) and \(2.80\) f. \(24 \mathrm{df}\), to the right of \(2.80\) g. \(10 \mathrm{df}\), to the left of \(-1.81\)

The article "Nine Out of Ten Drivers Admit in Survey to Having Done Something Dangerous" (Knight Ridder Newspapers, July 8,2005 ) reported the results of a survey of 1100 drivers. Of those surveyed, 990 admitted to careless or aggressive driving during the previous 6 months. Assuming that it is reasonable to regard this sample of 1100 as representative of the population of drivers, use this information to construct a \(99 \%\) confidence interval to estimate \(p\), the proportion of all drivers who have engaged in careless or aggressive driving in the previous 6 months.

The paper "The Curious Promiscuity of Queen Honey Bees (Apis mellifera): Evolutionary and Behavioral Mechanisms" (Annals of Zoology Fennici [2001]:255- 265) describes a study of the mating behavior of queen honeybees. The following quote is from the paper: Queens flew for an average of \(24.2 \pm 9.21\) minutes on their mating flights, which is consistent with previous findings. On those flights, queens effectively mated with \(4.6 \pm 3.47\) males (mean \(\pm \mathrm{SD})\). a. The intervals reported in the quote from the paper were based on data from the mating flights of \(n=\) 30 queen honeybees. One of the two intervals reported is stated to be a confidence interval for a population mean. Which interval is this? Justify your choice. b. Use the given information to construct a \(95 \%\) confidence interval for the mean number of partners on a mating flight for queen honeybees. For purposes of this exercise, assume that it is reasonable to consider these 30 queen honeybees as representative of the population of queen honeybees.

The Associated Press (December 16,1991 ) reported that in a random sample of 507 people, only 142 correctly described the Bill of Rights as the first 10 amendments to the U.S. Constitution. Calculate a \(95 \%\) confidence interval for the proportion of the entire population that could give a correct description.

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