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Determine the value of \(z^{*}\) such that a. \(-z^{*}\) and \(z^{*}\) separate the middle \(95 \%\) of all \(z\) values from the most extreme \(5 \%\) b. \(-z^{*}\) and \(z^{*}\) separate the middle \(90 \%\) of all \(z\) values from the most extreme \(10 \%\) c. \(-z^{*}\) and \(z^{*}\) separate the middle \(98 \%\) of all \(z\) values from the most extreme \(2 \%\) d. \(-z^{*}\) and \(z^{*}\) separate the middle \(92 \%\) of all \(z\) values from the most extreme \(8 \%\)

Short Answer

Expert verified
a. \(z^{*}\) ≈ 1.96 for 95% confidence b. \(z^{*}\) ≈ 1.645 for 90% confidence c. \(z^{*}\) ≈ 2.33 for 98% confidence d. \(z^{*}\) ≈ 1.75 for 92% confidence

Step by step solution

01

Determine the Corresponding Percentiles

The standard normal tables or calculator functions will often give you the area to the left of the desired z-score we want. In other words, they give us the percentile rank. So, we have to convert the mid-range percentages given to percentile ranks. For example, if the middle 95 % of all z values is to be covered, then we have to find the z-score that leaves 2.5 % of values in either tails since 100% - 95% = 5%, and that 5% is split between two tails.
02

Look up the z-scores

Using either a standard normal table or an online z-score calculator, look up the percentiles from step 1 to find the corresponding z-scores \(z^{*}\). They will be the same magnitude but opposite in sign, i.e \(-z^{*}\) and \(z^{*}\).
03

Repeat for all scenarios

Repeat the previous steps for the other scenarios given in the exercise

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentiles
Percentiles are a way to understand the position of a particular data point within a larger set of data. They indicate the percentage of data points that fall below a specific value. For example, if a score is in the 90th percentile, this means it is higher than 90% of the other scores. Percentiles are especially useful in statistics because they help compare different data points across a distribution.
When it comes to the standard normal distribution, converting a percentage to a percentile rank is the first key step in finding the corresponding z-score. By identifying how a specific inclusion percentage relates to the distribution, you can determine what z-score separates that middle percentage from the rest. Understanding percentiles is a fundamental skill for working with data distributions.
Standard Normal Distribution
The standard normal distribution is a special type of normal distribution that has a mean (\(\mu\)) of 0 and a standard deviation (\(\sigma\)) of 1. This makes it easier to determine probability values and compare data sets. In this distribution, the spread of data forms a bell shape, often referred to as a 'bell curve'.
Using the standard normal distribution is crucial in finding z-scores, as it allows one to interpret and compare how individual scores relate to the average performance. Through z-scores, data can be standardized, meaning different data sets can be compared easily. This standardization is helpful in scenarios where you need to determine which data points fall within certain percentile ranks, such as in the exercise.
Tail Values
Tail values refer to the portions of a probability distribution that lie beyond a specified percentile. In the context of a normal distribution, they usually represent the extreme lower and upper ends of the distribution. Understanding tail values is essential for identifying outliers or extreme results in a data set, particularly in studies that require tail probability analysis.
For example, if you need to separate a middle percentage of data from the distribution, the tail values represent the remainder that lies outside of that central range. When solving for z-scores like \(-z^{*}\) and \(z^{*}\), the tails constitute the extreme percentages outside the middle percentiles, which can provide insights into how frequently extreme values occur.
Extreme Values
Extreme values are those that lie in the tails of a distribution. They are distinct from the majority of the data and can signal rare or significant phenomena. Identifying these values is key in understanding the variability and range of a data set.
In the context of a z-score analysis, understanding extreme values involves separating these from the central majority of data. The exercise involves finding critical z-score cutoffs like \(-z^{*}\) and \(z^{*}\), which help to define the range of normal versus extreme outcomes. Recognizing and analyzing extreme values helps in assessing probabilities and making statistical inferences about data distributions.

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Most popular questions from this chapter

The states of Ohio, Iowa, and Idaho are often confused, probably because the names sound so similar. Each year, the State Tourism Directors of these three states drive to a meeting in one of the state capitals to discuss strategies for attracting tourists to their states so that the states will become better known. The location of the meeting is selected at random from the three state capitals. The shortest highway distance from Boise, Idaho to Columbus, Ohio passes through Des Moines, Iowa. The highway distance from Boise to Des Moines is 1350 miles, and the distance from Des Moines to Columbus is 650 miles. Let \(d_{1}\) represent the driving distance from Columbus to the meeting, with \(d_{2}\) and \(d_{3}\) representing the distances from Des Moines and Boise, respectively. a. Find the probability distribution of \(d_{1}\) and display it in a table. b. What is the expected value of \(d_{1} ?\) c. What is the value of the standard deviation of \(d_{1}\) ? d. Consider the probability distributions of \(d_{2}\) and \(d_{3}\). Is either probability distribution the same as the probability distribution of \(d_{1}\) ? Justify your answer. e. Define a new random variable \(t=d_{1}+d_{2}\). Find the probability distribution of \(t\). f. For each of the following statements, indicate if the statement is true or false and provide statistical evidence to support your answer. i. \(E(t)=E\left(d_{1}\right)+E\left(d_{2}\right)\) (Hint: \(E(t)\) is the expected value of \(t\) and another way of denoting the mean of \(t\).) ii. \(\sigma_{t}^{2}=\sigma_{d_{1}}^{2}+\sigma_{d_{3}}^{2}\)

The article "Modeling Sediment and Water Column Interactions for Hydrophobic Pollutants" (Water Research [1984]: \(1169-1174\) ) suggests the uniform distribution on the interval from \(7.5\) to 20 as a model for \(x=\) depth (in centimeters) of the bioturbation layer in sediment for a certain region. a. Draw the density curve for \(x\). b. What is the height of the density curve? c. What is the probability that \(x\) is at most 12 ? d. What is the probability that \(x\) is between 10 and 15 ? Between 12 and 17 ? Why are these two probabilities equal?

Suppose that \(65 \%\) of all registered voters in a certain area favor a 7 -day waiting period before purchase of a handgun. Among 225 randomly selected registered voters, what is the probability that a. At least 150 favor such a waiting period? b. More than 150 favor such a waiting period? c. Fewer than 125 favor such a waiting period?

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuality, each one could arrive on Wednesday (W), Thursday (I), Friday (F), or Saturday (S). Suppose that the two magazines arrive independently of one another and that for each magazine \(P(\mathrm{~W})\) \(=.4, P(\mathrm{~T})=.3, P(\mathrm{~F})=.2\), and \(P(S)=.1 .\) Define a random variable \(y\) by \(y=\) the number of days beyond Wednesday that it takes for both magazines to arrive. For example, if the first magazine arrives on Friday and the second magazine arrives on Wednesday, then \(y=2\), whereas \(y=1\) if both magazines arrive on Thursday. Obtain the probability distribution of \(y\). (Hint: Draw a tree diagram with two generations of branches, the first labeled with arrival days for Magazine 1 and the second for Magazine 2.)

Let \(z\) denote a random variable having a normal distribution with \(\mu=0\) and \(\sigma=1 .\) Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50\) )

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