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Twenty-five percent of the customers of a grocery store use an express checkout. Consider five randomly selected customers, and let \(x\) denote the number among the five who use the express checkout. a. What is \(p(2)\), that is, \(P(x=2) ?\) b. What is \(P(x \leq 1)\) ? c. What is \(P(2 \leq x)\) ? (Hint: Make use of your answer from Part (b).) d. What is \(P(x \neq 2)\) ?

Short Answer

Expert verified
The solution to the problem is \(p(2)\) as calculated in Step 1, \(P(x \leq 1)\) as calculated in Step 2, \(P(2 \leq x)\) as evaluated in Step 3, and \(P(x \neq 2)\) as calculated in Step 4.

Step by step solution

01

Calculation of \(p(2)\)

We start by calculating the probability that exactly two customers use the express checkout. For that, we use the formula of Binomial distribution: \[P(x=k) = C(n, k) * p^k * (1-p)^{n-k}\], where \(C(n, k)\) denotes the binomial coefficient which we calculate using the formula: \(C(n, k) = n! / (k!*(n-k)!)\). By substituting the given values, \(n=5\), \(k=2\) and \(p=0.25\) into the formula, we find \[P(x=2) = C(5, 2) * (0.25)^2 * (0.75)^3\].
02

Calculation of \(P(x \leq 1)\)

To calculate the probability that at most one customer uses the express checkout, we sum the probabilities of 0 and 1 successes: \[P(x \leq 1) = P(x=0) + P(x=1)\]. We again use the Binomial distribution formula to calculate both \(P(x=0)\) and \(P(x=1)\).
03

Calculation of \(P(2 \leq x)\)

To calculate the probability that at least two customers use the express checkout, we subtract probabilities till \(x=1\) from 1, by making use of the complement rule: \[P(2 \leq x) = 1 - P(x \leq 1)\].
04

Calculation of \(P(x \neq 2)\)

Finally, to calculate the probability that the number of customers using express checkout is not 2, we use the complement rule again: \[P(x \neq 2) = 1- P(x= 2)\]. So we subtract the value calculated in Step 1 from 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability calculations are essential for determining the likelihood of different outcomes in a random experiment. In this context, we focus on a situation where only 25% of the customers at a grocery store use express checkout lines. These calculations help us discover the probability of a specific number of customers using the express checkout out of a random sample of five customers.

We rely on the _binomial distribution_, a statistical method used for modeling the number of successful outcomes in experiments with fixed trials, where each trial has the same probability of success. The experiment's trials can either be a success (a customer uses the express checkout) or a failure (a customer doesn't use it).

To calculate the probability of exactly two customers using express checkout, we apply the binomial formula: \[ P(x=k) = C(n, k) * p^k * (1-p)^{n-k} \] Here,
  • \( n \) is the total number of trials (5 customers),
  • \( k \) is the number of successes sought (2 customers),
  • \( p \) is the probability of success on each trial (0.25).
By understanding the calculations, students can better see how these probabilities connect to real-world scenarios, such as assessing service demand at grocery stores.
Express Checkout
Express checkout lanes serve a specific function in supermarkets, intended to provide faster service for customers purchasing a limited number of items. These lanes are typically labeled with restrictions, such as "10 items or less," and appeal to customers in a hurry. Given that 25% of customers opt for this option, it's a useful example in probability exercises.

In the provided problem, we explore how express checkouts relate to binomial probability distributions. By considering five randomly selected customers, one can calculate various probabilities of a certain number of these customers opting for express checkout.
  • "Express" in this case, symbolizes a transfer of a realistic store scenario to a mathematical model.
  • Understanding the setup allows students to connect probability theories with everyday shopping experiences.
The calculations we pursue, such as determining the likelihood of 0, 1, or 2 out of 5 customers using express lines, offer insights into how stores can plan for efficient customer service.
Complement Rule
The complement rule is a powerful concept in probability that simplifies calculations by providing a new perspective. It states that the probability of an event not happening equals one minus the probability of the event happening.

This idea was applied multiple times in our exercise. For example, when determining \( P(2 \leq x) \), or the probability that at least two customers use the express checkout, we took the complement by subtracting the probability of 0 or 1 express users from 1:
\[ P(2 \leq x) = 1 - P(x \leq 1) \]
The complement rule simplifies tasks significantly when calculating probabilities for "at least" or "at most" scenarios, which can otherwise be laborious.

By mastering this technique, students can handle broad classes of probability questions with ease, quickly shifting their viewpoint from what seems complex to what's more straightforward, and often gaining a fresh insight into real-world statistics.

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Most popular questions from this chapter

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