/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 The paper cited in Exercise \(4.... [FREE SOLUTION] | 91Ó°ÊÓ

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The paper cited in Exercise \(4.65\) also reported values of single-leg power for a low workload. The sample mean for \(n=13\) observations was \(\bar{x}=119.8\) (actually \(119.7692\) ), and the 14 th observation, somewhat of an outlier, was \(159 .\) What is the value of \(\bar{x}\) for the entire sample?

Short Answer

Expert verified
The value of \(\bar{x}\) for the entire sample is obtained through these steps. The results show how new data can impact your overall statistics.

Step by step solution

01

Calculate Total of First 13 Observations

First, the total sum of the first 13 observations should be calculated. To do that, simply multiply the known average of 13 observations (\(\bar{x} = 119.8\)) by the number of these observations (n = 13).
02

Include the 14th Observation

Now, you need to include the 14th observation in your overall total. So you add the value of the 14th observation (159) to the total sum obtained in Step 1.
03

Calculate the Mean for All Observations

Finally, the new sample mean (\(\bar{x}\)) is calculated for all 14 observations by dividing the sum obtained in Step 2 by 14.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Outlier Detection
Understanding and identifying outliers is crucial in data analysis. An outlier is an observation that is significantly different from the other values in a dataset, and it can have a substantial impact on statistical results, such as the calculation of the mean.

To detect an outlier, you can employ various statistical methods. One common technique involves the interquartile range (IQR), where data points outside 1.5 times the IQR below the first quartile or above the third quartile are considered outliers. Another method is the standard deviation approach, where observations more than three standard deviations from the mean are outliers. Additionally, visual methods like boxplots provide a graphical representation of potential outliers.

In our exercise, the 14th observation with a value of 159 is mentioned as 'somewhat of an outlier'. To determine if it's a true outlier, one would typically analyze the spread and distribution of all observations. The presence of an outlier might signal unusual conditions or errors in data collection, requiring further investigation to understand its source and decide whether to include or exclude it from analysis.
Statistical Analysis
Statistical analysis involves collecting, summarizing, and interpreting data to discover underlying patterns and trends. It plays a pivotal role in decision-making across various fields such as science, business, and public policy. Techniques range from simple descriptive statistics, like the mean or median, to complex inferential statistics, used to make predictions or test hypotheses.

For instance, calculating a sample mean, as seen in our exercise, is a fundamental statistical technique that allows us to estimate the central tendency of a data set. However, it's important to note that the mean is sensitive to outliers, which can skew the results. Alternative measures such as the median may sometimes be more appropriate to represent the central value of a data set. In practice, the choice of statistical methods should align with the nature of the data and the research question at hand.
Data Analysis
Data analysis is a comprehensive process of inspecting, cleansing, transforming, and modeling data with the objective of discovering useful information, informing conclusions, and supporting decision-making. It starts with data collection and moves through various stages such as data cleaning, which involves removing or correcting inaccurate records from a database.

In the context of our original exercise, we see the practical application of data analysis in the calculation of the sample mean. When the task involves combining a series of observations and incorporating a potential outlier, the robustness of the data analysis process is tested. Good data analysis will always question irregularities and seek to understand their impact. With the use of statistical software or even a simple spreadsheet, one can compute measures of central tendency and variation, which can guide further analysis and provide insight into the significance of variability in data.

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Most popular questions from this chapter

Suppose that your younger sister is applying for entrance to college and has taken the SATs. She scored at the 8 ard percentile on the verbal section of the test and at the 94 th percentile on the math section of the test. Because you have been studying statistics, she asks you for an interpretation of these values. What would you tell her?

The standard deviation alone does not measure relative variation. For example, a standard deviation of \(\$ 1\) would be considered large if it is describing the variability from store to store in the price of an ice cube tray. On the other hand, a standard deviation of \(\$ 1\) would be considered small if it is describing store-to-store variability in the price of a particular brand of freezer. A quantity designed to give a relative measure of variability is the coefficient of variation. Denoted by CV, the coefficient of variation expresses the standard deviation as a percentage of the mean. It is defined by the formula \(C V=100\left(\frac{s}{\bar{x}}\right)\). Consider two samples. Sample 1 gives the actual weight (in ounces) of the contents of cans of pet food labeled as having a net weight of 8 ounces. Sample 2 gives the actual weight (in pounds) of the contents of bags of dry pet food labeled as having a net weight of 50 pounds. The weights for the two samples are \(\begin{array}{lrrrrr}\text { Sample 1 } & 8.3 & 7.1 & 7.6 & 8.1 & 7.6 \\ & 8.3 & 8.2 & 7.7 & 7.7 & 7.5 \\ \text { Sample 2 } & 52.3 & 50.6 & 52.1 & 48.4 & 48.8 \\ & 47.0 & 50.4 & 50.3 & 48.7 & 48.2\end{array}\) a. For each of the given samples, calculate the mean and the standard deviation. b. Compute the coefficient of variation for each sample. Do the results surprise you? Why or why not?

The chapter introduction gave the accompanying data on the percentage of those eligible for a lowincome subsidy who had signed up for a Medicare drug plan in each of 49 states (information was not available for Vermont) and the District of Columbia (USA Today. May \(9.2006\) ). \(\begin{array}{llllllll}24 & 27 & 12 & 38 & 21 & 26 & 23 & 33 \\ 19 & 19 & 26 & 28 & 16 & 21 & 28 & 20 \\ 21 & 41 & 22 & 16 & 29 & 26 & 22 & 16 \\ 27 & 22 & 19 & 22 & 22 & 22 & 30 & 20 \\ 21 & 34 & 26 & 20 & 25 & 19 & 17 & 21 \\ 27 & 19 & 27 & 34 & 20 & 30 & 20 & 21\end{array}\) 19 18 ( $$ 14 $$ a. Compute the mean for this data set. b. The article stated that nationwide, \(24 \%\) of those eligible had signed up. Explain why the mean of this data set from Part (a) is not equal to 24 . (No information was available for Vermont, but that is not the reason that the mean differs-the \(24 \%\) was calculated excluding Vermont.)

Age at diagnosis for each of 20 patients under treatment for meningitis was given in the paper "Penidlin in the Treatment of Meningitis" (journal of the American Medical Association [1984]: \(1870-1874\) ). The ages (in years) were as follows: $$ \begin{array}{lllllllllll} 8 & 25 & 19 & 23 & 20 & 69 & 18 & 21 & 18 & 20 & 18 \\ 0 & 18 & 19 & 28 & 17 & 18 & 18 & & & & \end{array} $$ \(\begin{array}{ll}18 & 18 \\ 18 & 20\end{array}\) a. Calculate the values of the sample mean and the standard deviation. b. Calculate the \(10 \%\) trimmed mean. How does the value of the trimmed mean compare to that of the sample mean? Which would you recommend as a measure of center? Explain. c. Compute the upper quartile, the lower quartile, and the interquartile range. d. Are there any mild or extreme outliers present in this data set? e. Construct the boxplot for this data set.

The technical report "Ozone Season Emissions by State" (U.S. Environmental Protection Agency. 2002) gave the following nitrous oxide emissions (in thousands of tons) for the 48 states in the continental U.S. states: \(\begin{array}{rrrrrrrrrrr}76 & 22 & 40 & 7 & 30 & 5 & 6 & 136 & 72 & 33 & 0 \\\ 89 & 136 & 39 & 92 & 40 & 13 & 27 & 1 & 63 & 33 & 60 \\ 27 & 16 & 63 & 32 & 20 & 2 & 15 & 36 & 19 & 39 & 130 \\ 40 & 4 & 85 & 38 & 7 & 68 & 151 & 32 & 34 & 0 & 6\end{array}\) \(\begin{array}{rr}40 & 4 \\ 43 & 89\end{array}\) $$ 340 $$ Use these data to construct a boxplot that shows outliers. Write a few sentences describing the important characteristics of the boxplot.

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