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The authors of the article "Perceived Risks of Heart Disease and Cancer Among Cigarette Smokers" (journal of the American Medical Association [1999]: 1019-1021) expressed the concern that a majority of smokers do not view themselves as being at increased risk of heart disease or cancer. A study of 737 current smokers selected at random from U.S. households with telephones found that of the 737 smokers surveyed, 295 indicated that they believed they have a higher than average risk of cancer. Do these data suggest that \(p\), the true proportion of smokers who view themselves as being at increased risk of cancer is in fact less than . 5 , as claimed by the authors of the paper? Test the relevant hypotheses using \(\alpha=.05\).

Short Answer

Expert verified
In order to determine whether the proportion of smokers who believe they are at a higher risk of cancer is less than 0.5 as claimed by the authors, we perform a hypothesis test for the proportion. After defining the null and alternative hypotheses, calculating the z score, computing the P-value and comparing it with the given significance level, we make a conclusion whether to reject or fail to reject the null hypothesis. The exact decision depends on the computed P-value.

Step by step solution

01

Defining the Hypotheses

Begin the problem by defining the null hypothesis and the alternative hypothesis. Here, the null hypothesis (\(H_0\)) can be that the proportion of smokers who perceive a higher risk of cancer is equal to 0.5 (p = 0.5). And the alternative hypothesis (\(H_1\)) is the claim we are testing, that the true proportion of smokers who view themselves at higher risk is less than 0.5 (p < 0.5).
02

Calculating the Test Statistic

The next step involves calculations for the test statistic. From the given data, we define our values as follows: n(sample size) = 737, x(number of positive outcomes) = 295, and p_0 (null hypothesis proportion) = 0.5. The test statistic (z) for hypothesis testing of a proportion is given by: \(Z = \frac{p̂ - p_0}{\sqrt{p_0*(1-p_0)/n}}\), where p̂ is the sample proportion (x/n). So first, calculate p̂ = x/n.
03

Compute the Test Statistic and P-value

After calculating the sample proportion (\(p̂\)), substitute \(p̂\), \(p_0\) and n in the equation for Z to find the test statistic. The P-value is the probability that a random variable is equal to or less critical than the observed test statistic, assuming the null hypothesis is true. In our scenario, the test statistic follows a standard normal distribution, because the Central Limit Theorem applies. Therefore, it is possible to use a standard normal distribution (Z-distribution) to find the P-value. With \(\alpha = .05\), if the P-value is less than \(\alpha\), we reject the null hypothesis.
04

Decision

The final step is to compare the P-value with \(\alpha\). If the P-value < \(\alpha\), then we reject the null hypothesis \(H_0\). If not, then we fail to reject the null hypothesis. This leads us to the conclusion about the smokers' perception of being at a higher risk for cancer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Hypothesis Test
When researchers want to make inferences about the population proportion based on a sample data, they use a proportion hypothesis test. In the context of the exercise involving smokers' perception of cancer risk, we're interested in whether the true proportion of smokers who believe they are at higher risk of cancer is different from what is expected under the null hypothesis.

To conduct this test effectively, we consider the entire process of hypothesis testing which includes defining null and alternative hypotheses, calculating a test statistic based on the sample data, and interpreting the p-value in relation to the significance level, \( \alpha \). It's important to make sure that the sample is large enough to use the test, generally following the rule that both the expected number of successes (\(np_0\)) and failures (\(n(1-p_0)\)) are greater than 5.
Null and Alternative Hypotheses
The null hypothesis (\(H_0\)) is a statement of no effect or no difference, which serves as a starting assumption for the statistical test. In our exercise, the null hypothesis is that the true proportion of smokers who view themselves at increased risk of cancer, \(p\), equals 0.5. The alternative hypothesis (\(H_1\)) is what you suspect might be true instead and is contrary to the null hypothesis. Here, we're testing the claim that actually fewer than half of smokers (\(p<0.5\)) perceive themselves at higher risk.

Defining these hypotheses correctly is foundational to the testing process, setting the stage for either rejection or failure to reject the null based on the evidence provided by our sample.
Test Statistic Calculation
Calculating the test statistic is a core step in hypothesis testing. It's a standardized value that helps to determine how far our sample statistic (in this case, the sample proportion) deviates from the null hypothesis. Using the formula for the test statistic for a proportion \[Z = \frac{\hat{p} - p_0}{\sqrt{{p_0(1-p_0)/n}}}\], where \(\hat{p}\) is the sample proportion and \(p_0\) is the hypothesized population proportion, we compare the calculated test statistic against a critical value from the standard normal distribution.

This calculation provides a bridge between our sample data and the realm of probability, which is key to making an inference about the entire population from which the sample was drawn.
P-value Interpretation
The p-value is the probability of obtaining test results at least as extreme as the results actually observed, under the assumption that the null hypothesis is correct. Interpretation of the p-value is crucial: a small p-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis. Therefore, we would reject the null and accept the alternative hypothesis as more likely. Contrastingly, a large p-value suggests weak evidence against the null hypothesis, so we fail to reject it.

In the exercise, if the calculated p-value is less than or equal to \(\alpha=0.05\), it suggests that it's unlikely the observed sample came from a population where the true proportion is 0.5. Thus, supporting the research claim and leading us to reject the null hypothesis in favor of the alternative.

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Most popular questions from this chapter

A manufacturer of hand-held calculators receives large shipments of printed circuits from a supplier. It is too costly and time-consuming to inspect all incoming circuits, so when each shipment arrives, a sample is selccted for inspcction. Information from the samplc is then used to test \(H_{0}: p=.01\) versus \(H_{a}: p>.01\), where \(p\) is the actual proportion of defective circuits in the shipment. If the null hypothesis is not rejected, the shipment is accepted, and the circuits are used in the production of calculators. If the null hypothesis is rejected, the entire shipment is returned to the supplier because of inferior quality. (A shipment is defined to be of inferior quality if it contains more than \(1 \%\) defective circuits.) a. In this context, define Type I and Type II errors. b. From the calculator manufacturer's point of view, which type of error is considered more serious? ca From the printed circuit supplier's point of view, which type of error is considered more serious?

Give as much information as you can about the \(P\) -value of a \(t\) test in each of the following situations: a. Two-tailed test, \(\mathrm{df}=9, t=0.73\) b. Upper-tailed test, \(\mathrm{df}=10, t=-0.5\) c. Lower-tailed test, \(n=20, t=-2.1\) d. Lower-tailed test, \(n=20, t=-5.1\) e. Two-tailed test, \(n=40, t=1.7\)

Students at the Akademia Podlaka conducted an experiment to determine whether the Belgium-minted Euro coin was equally likely to land heads up or tails up. Coins were spun on a smooth surface, and in 250 spins, 140 landed with the heads side up (New Scientist, January 4,2002 ). Should the students interpret this result as convincing evidence that the proportion of the time the coin would land heads up is not. 5? Test the relevant hypotheses using \(\alpha=.01\). Would your conclusion be different if a significance level of \(.05\) had been used? Explain.

A television manufacturer claims that (at least) \(90 \%\) of its TV sets will need no service during the first 3 years of operation. A consumer agency wishes to check this claim, so it obtains a random sample of \(n=100\) purchasers and asks each whether the set purchased needed repair during the first 3 years after purchase. Let \(\hat{p}\) be the sample proportion of responses indicating no repair (so that no repair is identified with a success). Let \(p\) denote the actual proportion of successes for all sets made by this manufacturer. The agency does not want to claim false advertising unless sample evidence strongly suggests that \(p<.9\). The appropriate hypotheses are then \(H_{0}: p=.9\) versus \(H_{a}: p<.9\). a. In the context of this problem, describe Type I and Type II errors, and discuss the possible consequences of each. b. Would you recommend a test procedure that uses \(\alpha=.10\) or one that uses \(\alpha=.01 ?\) Explain.

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