/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A certain university has decided... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A certain university has decided to introduce the use of plus and minus with letter grades, as long as there is evidence that more than \(60 \%\) of the faculty favor the change. A random sample of faculty will be selected, and the resulting data will be used to test the relevant hypotheses. If \(p\) represents the proportion of all faculty that favor a change to plus-minus grading, which of the following pair of hypotheses should the administration test: $$ H_{0}: p=.6 \text { versus } H_{a}: p<.6 $$ or $$ H_{0}: p=.6 \text { versus } H_{a}: p>.6 $$

Short Answer

Expert verified
The correct hypotheses to test are \(H_0\): \(p = .6\) versus \(H_a\): \(p > .6\).

Step by step solution

01

Understanding the problem

The university wants introduce the use of plus and minus with letter grades given one condition: more than 60% of the faculty favor the change. This means that the university will consider to move forward with this change if the proportion (p) of the faculty that is in favor of the change is greater than 60%.
02

Formulating Hypotheses

Based on the university's condition, the hypotheses should capture the direction of the change they're interested in. So this leads to:Null Hypothesis \(H_0\): \(p = 0.6\), this assumes that exactly 60% of all faculty favor the change, which means there's no significant evidence to introduce the new grading system.Alternative Hypothesis \(H_a\): \(p > 0.6\), assuming that more than 60% favor the change, providing statistical significance towards introducing the new grading system.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Testing
Proportion testing is a powerful statistical method used when we want to understand if a certain proportion of a population has a particular attribute. In the context of our exercise, proportion testing is used to determine the proportion of faculty members who favor a new grading system. This involves statistical techniques to analyze the data obtained from a sample and make inferences about the entire population.

The core idea is to compare the observed proportion from our sample to a hypothetical proportion stated in the null hypothesis. In this case, the hypothetical proportion is 60%. When conducting proportion tests, we typically use a sample proportion that is calculated by the formula \( \hat{p} = \frac{x}{n} \), where \(x\) is the number of favorable outcomes, and \(n\) is the total number of observations in the sample.

Proportion testing is essential because it helps in decision-making, enabling the university to determine if their strategy should change based on faculty preferences. It bridges the gap between what is observed in a sample and what can be inferred about the broader population, ensuring more confident and backed decisions.
Statistical Significance
When we talk about statistical significance in hypothesis testing, we're focusing on how likely it is that the observed results are due to chance. In the university's scenario, statistical significance means verifying whether the proportion of faculty supporting the new grading approach is genuinely greater than 60%.

Statistical significance is typically assessed using a p-value, which tells us the probability of obtaining our sample results assuming the null hypothesis is true. If this p-value is less than a predetermined significance level (often set at 0.05), we have enough evidence to reject the null hypothesis in favor of the alternative hypothesis.

Understanding statistical significance is important because it serves as a key to validating results and guiding decisions. It helps ensure that the changes implemented based on sample data genuinely reflect the preferences or behaviors of the wider faculty group, minimizing the risk of chance-driven decisions.
Null and Alternative Hypothesis
The null hypothesis, denoted as \(H_0\), and the alternative hypothesis, denoted as \(H_a\), form the foundation of any hypothesis-testing procedure. In this exercise, the hypotheses are specifically crafted to reflect the university’s need for more than 60% faculty approval to proceed with the grading system change.

The null hypothesis \(H_0: p = 0.6\) assumes that exactly 60% of faculty members favor the change, implying no notable evidence supports reconsidering the grading system. The alternative hypothesis \(H_a: p > 0.6\), on the other hand, suggests that more than 60% of faculty favor the change, providing a statistical basis for adopting the new system.

It's crucial to frame hypotheses accurately, as they guide the entire statistical process. The null hypothesis serves as a default stance that remains unless data provides sufficient support for the alternative hypothesis. This approach helps enrich critical decision-making processes by relying on evidence rather than intuition or incomplete data.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a representative sample of 1000 adult Americans, only 430 could name at least one justice who is currently serving on the U.S. Supreme Court (Ipsos, January 10, 2006 ). Using a significance level of .01, carry out a hypothesis test to determine if there is convincing evidence to support the claim that fewer than half of adult Americans can name at least one justice currently serving on the Supreme Court.

An article titled "Teen Boys Forget Whatever It Was" appeared in the Australian newspaper The Mercury (April 21, 1997). It described a study of academic performance and attention span and reported that the mean time to distraction for teenage boys working on an independent task was 4 minutes. Although the sample size was not given in the article, suppose that this mean was based on a random sample of 50 teenage Australian boys and that the sample standard deviation was \(1.4\) minutes. Is there convincing evidence that the average attention span for teenage boys is less than 5 minutes? Test the relevant hypotheses using \(\alpha=.01\).

Researchers at the University of Washington and Harvard University analyzed records of breast cancer screening and diagnostic evaluations ("Mammogram Cancer Scares More Frequent than Thought," USA Today. April 16, 1998). Discussing the benefits and downsides of the screening process, the article states that, although the rate of false-positives is higher than previously thought, if radiologists were less aggressive in following up on suspicious tests, the rate of false-positives would fall but the rate of missed cancers would rise. Suppose that such a screening test is used to decide between a null hypothesis of \(H_{0}:\) no cancer is present and an alternative hypothesis of \(H_{a}\) : cancer is present. (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) a. Would a false-positive (thinking that cancer is present when in fact it is not) be a Type I error or a Type II error? b. Describe a Type I error in the context of this problem, and discuss the consequences of making a Type I error. c. Describe a Type II error in the context of this problem, and discuss the consequences of making a Type II error. d. What aspect of the relationship between the probability of Type I and Type II errors is being described by the statement in the article that if radiologists were less aggressive in following up on suspicious tests, the rate of false-positives would fall but the rate of missed cancers would rise?

Ann Landers, in her advice column of October 24,1994 (San Luis Obispo Telegram-Tribune), described the reliability of DNA paternity testing as follows: "To get a completely accurate result, you would have to be tested, and so would (the man) and your mother. The test is \(100 \%\) accurate if the man is not the father and \(99.9 \%\) accurate if he is." a. Consider using the results of DNA paternity testing to decide between the following two hypotheses: \(H_{0}:\) a particular man is the father \(H_{a}\) : a particular man is not the father In the context of this problem, describe Type I and Type II errors. (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) b. Based on the information given, what are the values of \(\alpha\), the probability of a Type I error, and \(\beta\), the probability of a Type II error? c. Ann Landers also stated, "If the mother is not tested, there is a \(0.8 \%\) chance of a false positive." For the hypotheses given in Part (a), what is the value of \(\beta\) if the decision is based on DNA testing in which the mother is not tested?

Duck hunting in populated areas faces opposition on the basis of safety and environmental issues. In a survey to assess public opinion regarding duck hunting on Morro Bay (located along the central coast of California), a random sample of 750 local residents included 560 who strongly opposed hunting on the bay. Does this sample provide sufficient evidence to conclude that the majority of local residents oppose hunting on Morro Bay? Test the relevant hypotheses using \(\alpha=.01\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.