/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 According to the article "Workah... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

According to the article "Workaholism in Organizations: Gender Differences" (Sex Roles [1999]: \(333-346\) ), the following data were reported on 1996 income for random samples of male and female MBA graduates from a certain Canadian business school: \begin{tabular}{lccc} & \(\boldsymbol{N}\) & \(\overline{\boldsymbol{x}}\) & \(\boldsymbol{s}\) \\ \hline Males & 258 & \(\$ 133,442\) & \(\$ 131,090\) \\ Females & 233 & \(\$ 105,156\) & \(\$ 98,525\) \\ \hline \end{tabular} Note: These salary figures are in Canadian dollars. a. Test the hypothesis that the mean salary of male MBA graduates from this school was in excess of \(\$ 100,000\) in \(1996 .\) b. Is there convincing evidence that the mean salary for all female MBA graduates is above \(\$ 100,000 ?\) Test using \(\alpha=.10\) c. If a significance level of \(.05\) or \(.01\) were used instead of \(.10\) in the test of Part (b), would you still reach the same conclusion? Explain.

Short Answer

Expert verified
a) Yes, the mean salary of male MBA graduates was significantly more than \$100,000 in 1996. b) Based on the significance level \(\alpha = 0.10\), the mean salary for female MBA graduates was not significantly above \$100,000 in 1996. c) With a significance level of \(0.05\) or \(0.01\), the decision might change, depending on the value of the test statistic.

Step by step solution

01

Hypothesis Formulation for Male Graduates

Formulate the null and alternative hypothesis. Here, we want to test whether the mean salary of male MBA graduates was more than \$100,000. The null hypothesis (\(H_0\)) assumes that the mean is \$100,000, and the alternative hypothesis (\(H_a\)) is that the mean is more than \$100,000. In symbols, this is: \(H_0: \mu = \$100,000\), \(H_a: \mu > \$100,000\).
02

Test Statistic Calculation for Male Graduates

Calculate the test statistic using the formula \(Z = (\overline{x} - \mu_0) / (s/ \sqrt{N})\) where \(\overline{x}\) is the sample mean, \(\mu_0\) is the hypothesized population mean from \(H_0\), \(s\) is the standard deviation and \(N\) is the sample size. Substitute with the provided values into the formula.
03

Decision for Male Graduates

Compare the calculated test statistic with the critical value from the standard normal distribution table (Z-table) for a one-tailed test. If the test statistic is greater than the critical value, we reject the null hypothesis. Since we don't have a significance level, we use \(0.05\) by default.
04

Hypothesis Formulation for Female Graduates

Formulate the null and alternative hypothesis for the female graduates. Here, we want to test whether the mean salary of female MBA graduates was more than \$100,000. The null hypothesis (\(H_0\)) assumes that the mean is \$100,000, and the alternative hypothesis (\(H_a\)) is that the mean is more than \$100,000. In symbols, this is: \(H_0: \mu = \$100,000\), \(H_a: \mu > \$100,000\).
05

Test Statistic Calculation for Female Graduates

Calculate the test statistic using the same formula as in Step 2 and insert the appropriate values for female graduates.
06

Decision for Female Graduates

Compare the calculated test statistic with the critical value at \(\alpha = 0.10\), since a significance level of \(0.10\) was provided for the female graduates. If the test statistic is greater than the critical value, we reject the null hypothesis.
07

Significance Level Change

If a different significance level such as \(0.05\) or \(0.01\) was used instead of \(0.10\), the critical value will be different. Compare the calculated test statistic with the new critical values. If it is greater than the critical value at \(0.01\) or \(0.05\), we would still reject the null hypothesis; otherwise, we won't.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Hypothesis Formulation
When we talk about statistical hypothesis formulation, it's all about setting up a starting assumption (called the null hypothesis) and an alternative one to test against it. In the context of income analysis for MBA graduates, the null hypothesis might state that the average income is a certain amount, say \$100,000. The alternative hypothesis would suggest that the actual average income is different from this amount, for example, it could be higher. This is represented symbolically as:
  • Null Hypothesis (\(H_0\)): \(\mu = \$100,000\)
  • Alternative Hypothesis (\(H_a\)): \(\mu > \$100,000\) (for testing if the income is greater).

It's crucial to define these hypotheses clearly, as they set the stage for the entire testing process.
Test Statistic Calculation
Calculating the test statistic is a central part of any hypothesis test. The test statistic calculation helps us determine how far our sample statistic is from the null hypothesis's proposed value, measured in standard error units. You do this by using a formula that incorporates the sample mean, hypothesized mean, sample standard deviation, and sample size. In mathematical terms, the formula is: \(Z = (\overline{x} - \mu_0) / (s/ \sqrt{N})\) where \(\overline{x}\) is the sample mean, \(\mu_0\) is the hypothesized mean, \(s\) is the sample standard deviation, and \(N\) is the sample size. This Z-score tells you how many standard deviations away from the hypothesized mean the sample mean lies.
Significance Level
The significance level, denoted by \(\alpha\), is the threshold for deciding whether or not to reject the null hypothesis. It represents the probability of rejecting the null hypothesis when it is in fact true, which is a type I error. Common choices for \(\alpha\) are 0.01, 0.05, and 0.10. Choosing a lower \(\alpha\) means being more conservative about claiming a result as significant — that is, requiring stronger evidence to reject the null hypothesis. When analyzing the MBA graduates’ incomes, setting different significance levels, such as 0.05 or 0.01 instead of 0.10, would require a larger test statistic to reject the null hypothesis and claim the incomes are significantly different from the hypothesized value.
MBA Graduates Income Analysis
Performing an income analysis on MBA graduates helps us understand the financial returns of obtaining an MBA degree. This kind of analysis often involves hypothesis testing to determine whether the average income of MBA graduates exceeds a certain benchmark. In our case, we are comparing it to a benchmark of \$100,000. This involves using sample data to make inferences about the population as a whole, considering factors such as mean income (\(\overline{x}\)) and variability (standard deviation, \(s\)). This analysis can help educational institutions and students make informed decisions about the value of an MBA program.
Gender Differences in Income
Investigating gender differences in income, especially among MBA graduates, involves exploring whether a gender pay gap exists and its extent. In our example, we compare the incomes of male and female MBA graduates using hypothesis testing. Recognizing potential differences can provide insights into the impact of gender on career progression and pay. It's not just about identifying the presence of a gap but also understanding the magnitude and causes to inform policies for achieving gender equity in the workplace.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An article titled "Teen Boys Forget Whatever It Was" appeared in the Australian newspaper The Mercury (April 21, 1997). It described a study of academic performance and attention span and reported that the mean time to distraction for teenage boys working on an independent task was 4 min. Although the sample size was not given in the article, suppose that this mean was based on a random sample of 50 teenage Australian boys and that the sample standard deviation was \(1.4\) min. Is there convincing evidence that the average attention span for teenage boys is less than 5 min? Test the relevant hypotheses using \(\alpha=.01\).

Duck hunting in populated areas faces opposition on the basis of safety and environmental issues. The San Luis Obispo Telegram-Tribune (June 18,1991 ) reported the results of a survey to assess public opinion regarding duck hunting on Morro Bay (located along the central coast of California). A random sample of 750 local residents included 560 who strongly opposed hunting on the bay. Does this sample provide sufficient evidence to conclude that the majority of local residents oppose hunting on Morro Bay? Test the relevant hypotheses using \(\alpha=.01\).

A television manufacturer claims that (at least) \(90 \%\) of its TV sets will need no service during the first 3 years of operation. A consumer agency wishes to check this claim, so it obtains a random sample of \(n=100\) purchasers and asks each whether the set purchased needed repair during the first 3 years after purchase. Let \(p\) be the sample proportion of responses indicating no repair (so that no repair is identified with a success). Let \(\pi\) denote the true proportion of successes for all sets made by this manufacturer. The agency does not want to claim false advertising unless sample evidence strongly suggests that \(\pi<.9 .\) The appropriate hypotheses are then \(H_{0}: \pi=.9\) versus \(H_{a}: \pi<.9\). a. In the context of this problem, describe Type \(I\) and Type II errors, and discuss the possible consequences of each. b. Would you recommend a test procedure that uses \(\alpha=.10\) or one that uses \(\alpha=.01 ?\) Explain.

According to the article "Which Adults Do Underage Youth Ask for Cigarettes?" (American Journal of \(P u b\) lic Health [1999]: \(1561-1564\) ), \(43.6 \%\) of the 149 18- to 19 -year-olds in a random sample have been asked to buy cigarettes for an underage smoker. a. Is there convincing evidence that fewer than half of 18 to 19 -year-olds have been approached to buy cigarettes by an underage smoker? b. The article went on to state that of the 110 nonsmoking 18 - to 19 -year- olds, only \(38.2 \%\) had been approached to buy cigarettes for an underage smoker. Is there evidence that less than half of nonsmoking 18 - to 19 -year- olds have been approached to buy cigarettes?

The article "Theaters Losing Out to Living Rooms" (San Luis Obispo Tribune, June 17,2005 ) states that movie attendance declined in 2005 . The Associated Press found that 730 of 1000 randomly selected adult Americans preferred to watch movies at home rather than at a movie theater. Is there convincing evidence that the majority of adult Americans prefer to watch movies at home? Test the relevant hypotheses using a \(.05\) significance level.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.