/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Explain why \(x\) is or is not a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why \(x\) is or is not a binomial random variable. (Hint: compare the characteristics of this experiment with those of a binomial experiment given in this section.) If the experiment is binomial, give the value of \(n\) and \(p\), if possible. A market research firm hires operators to conduct telephone surveys. The computer randomly dials a telephone number, and the operator asks the respondent whether or not he has time to answer some questions. Let \(x\) be the number of telephone calls made until the first respondent is willing to answer the operator's questions.

Short Answer

Expert verified
If so, determine the values of n and p. Answer: No, the given situation is not a binomial experiment because it does not have a fixed number of trials. Therefore, we cannot find the values of n and p.

Step by step solution

01

Determine if the experiment has a fixed number of trials

In this situation, the experiment continues until the first respondent is willing to answer the operator's questions. Therefore, the number of trials is not fixed, as the experiment could end on any trial with a successful respondent.
02

Determine if the experiment has two possible outcomes

Each telephone call has two possible outcomes: yes (success, the respondent is willing to answer questions) or no (failure, the respondent is not willing to answer questions). So, this criterion is satisfied.
03

Determine if the probability of success is constant

The probability of success (getting a respondent to answer questions) is assumed to be constant for each trial since the computer dials the telephone numbers randomly. So, this criterion is also satisfied.
04

Determine if the trials are independent

The trials are considered independent because the outcome of one telephone call does not affect the outcome of subsequent telephone calls. The computer dials each number randomly, and the respondents' willingness to answer questions should not be influenced by previous respondents. So, this criterion is also satisfied.
05

Conclusion

Although the experiment meets three out of four criteria of a binomial experiment, it fails the first one - having a fixed number of trials. Therefore, \(x\) is not a binomial random variable. Since \(x\) is not a binomial random variable, we cannot find the values of \(n\) and \(p\) for this experiment.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Success
Understanding the probability of success is crucial when dealing with binomial random variables. In a binomial experiment, each trial has only two possible outcomes - either success or failure. The probability of success, denoted by p, must remain constant for each trial. For example, if we were tossing a fair coin, the probability of getting a 'heads' would be 0.5 - this probability would not change regardless of how many times we toss the coin.

In the context of our exercise, the probability that a respondent is willing to answer questions during a telephone call is considered to be a success. If this probability remains the same with each call made by the operators, this component of a binomial experiment is satisfied. However, it's vital to remember that if the probability varies, the experiment cannot be categorized as binomial.
Independent Trials
Another cornerstone of binomial experiments is independent trials. This means the outcome of any given trial should not be influenced by the outcome of any other trial. Think of it like flipping a coin again: How the coin landed in the past won't affect how it will land on the next flip. Independence is key for a sequence of trials to fit the binomial model.

In the exercise, the random dialing of telephone numbers theoretically ensures the independence of each call's outcome. Since each call is treated as a separate event, with no bearing on the next call, this aspect aligns well with the criteria for a binomial experiment. Therefore, in our market research example, we can comfortably say the trial's independence criterion is met.
Fixed Number of Trials
A defining feature of a binomial experiment is a fixed number of trials, denoted by n. This means that before we begin the experiment, we must know exactly how many trials will be conducted. For instance, if we plan to roll a die 10 times, then our fixed number of trials is 10.

The exercise poses a situation where trials continue until a success is achieved, without a predetermined limit. This indefinite number of trials leads to variability, which deviates from the rigid structure of a binomial experiment where n is predetermined and constant. As a result, not having a fixed number of trials is where our telephone survey example diverges from being a binomial experiment.
Binomial Experiment Characteristics
Let's dive into the essential characteristics of a binomial experiment. For an experiment to be binomial, it must meet four criteria: a fixed number of trials, two possible outcomes per trial (success or failure), a constant probability of success, and independence of trials. These characteristics ensure that the mathematical model of the binomial distribution applies, which allows for calculating probabilities and other statistical measures.

Our telephone survey example satisfies the criteria for two outcomes, constant probability, and independent trials. However, as the exercise reveals, since the number of trials isn't fixed but continues until a respondent is found, the scenario cannot be modeled as a binomial experiment. In practical terms, this means that probabilities associated with x (the number of calls until the first success) cannot be calculated using a binomial distribution. This is an important nuance for students to grasp, as it determines the appropriate statistical methods to use in analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, the probability that their offspring will develop the disease is approximately .25. Suppose a husband and wife are both carriers of the disease and the wife is pregnant on three different occasions. If the occurrence of Tay-Sachs in any one offspring is independent of the occurrence in any other, what are the probabilities of these events? a. All three children will develop Tay-Sachs disease. b. Only one child will develop Tay-Sachs disease. c. The third child will develop Tay-Sachs disease, given that the first two did not.

Talking or texting on your cell phone can be hazardous to your health! A snapshot in USA Today reports that approximately \(23 \%\) of cell phone owners have walked into someone or something while talking on their phones. A random sample of \(n=8\) cell phone owners were asked if they had ever walked into something or someone while talking on their cell phone. The following printout shows the cumulative and individual probabilities for a binomial random variable with \(n=8\) and \(p=.23 .\) Cumulative Distribution Function Binomial with \(\mathrm{n}=8\) and \(\mathrm{p}=0.23\) $$ \begin{array}{rl} \text { X } & P(X \leq X) \\ \hline 0 & 0.12357 \\ 1 & 0.41887 \\ 2 & 0.72758 \\ 3 & 0.91201 \\ 4 & 0.98087 \\ 5 & 0.99732 \\ 6 & 0.99978 \\ 7 & 0.99999 \\ 8 & 1.00000 \end{array} $$ Probability Density Function Binomial with \(n=8\) and \(p=0.23\) $$ \begin{aligned} &\begin{array}{cc} x & P(X=x) \\ \hline 0 & 0.123574 \end{array}\\\ &\begin{array}{l} 0 & 0.123574 \\ 1 & 0.295293 \\ 2 & 0.308715 \\ 3 & 0.184427 \\ 4 & 0.068861 \\ 5 & 0.016455 \\ 6 & 0.002458 \\ 7 & 0.000210 \\ 8 & 0.000008 \end{array} \end{aligned} $$ a. Use the binomial formula to find the probability that one of the eight have walked into someone or something while talking on their cell phone. b. Confirm the results of part a using the printout. c. What is the probability that at least two of the eight have walked into someone or something while talking on their cell phone.

A roulette wheel contains 38 pocketsthe numbers 1 through \(36,0,\) and \(00 .\) The wheel is spun and the "winning" pocket is recorded, with any one pocket just as likely as any other. Suppose you bet \(\$ 5\) on the number 18 . The payoff on this type of bet is usually \(\$ 35\) for a \(\$ 1\) bet. What is your expected gain?

Seeds are often treated with a fungicide for protection in poor-draining, wet environments. In a small-scale trial, five treated seeds and five untreated seeds were planted in clay soil and the number of plants emerging from the treated and untreated seeds were recorded. Suppose the dilution was not effective and only four plants emerged. Let \(x\) represent the number of plants that emerged from treated seeds. a. Find the probability that \(x=4\). b. Find \(P(x \leq 3)\). c. Find \(P(2 \leq x \leq 3)\).

Draw five cards randomly from a standard deck of 52 cards, and let \(x\) be the number of red cards in the draw. Evaluate the probabilities in Exercises \(22-25\). \(P(x=3)\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.