/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Evaluate the binomial probabilit... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the binomial probabilities in Exercises \(16-19\). $$ C_{2}^{8}(.3)^{2}(.7)^{6} $$

Short Answer

Expert verified
Answer: The value of the binomial probability expression is approximately \(0.294237\).

Step by step solution

01

Calculate the number of combinations

In this case, we have \(n = 8\) and \(x = 2\). Using the formula for calculating the number of combinations: $$ C_{8}^{2} = \frac{8!}{2!(8-2)!} = \frac{8!}{2!6!} $$ Compute the factorials: $$ 8! = 8\times7\times6\times5\times4\times3\times2\times1 = 40320 $$ $$ 2! = 2\times1 = 2 $$ $$ 6! = 6\times5\times4\times3\times2\times1 = 720 $$ Now, compute the combination: $$ C_{8}^{2} = \frac{40320}{2\times720} = 28 $$
02

Evaluate the given expression

Now that we have the value of \(C_{8}^{2}\), we can replace it in the given expression: $$ 28(.3)^{2}(.7)^{6} $$ Evaluate the powers: $$ (.3)^{2} = 0.09,\quad(.7)^{6} = 0.117649 $$ Substitute these values back into the expression: $$ 28\times0.09\times0.117649 $$ And finally, evaluate the expression: $$ 28\times0.09\times0.117649 \approx 0.294237 $$ So, the value of the given binomial probability is approximately \(0.294237\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations and Permutations
When dealing with probability and statistics, understanding the difference between combinations and permutations is critical. Combinations refer to the selection of items where the order does not matter, whereas permutations are all about the order of selection.

For example, if you are choosing two fruits from a basket of apples, bananas, and cherries, the combination would be the pair regardless of whether you picked an apple first or a banana. In a permutation, picking an apple then a banana is different from picking a banana then an apple.

To calculate combinations, we use the formula \(C_n^x = \frac{n!}{x!(n - x)!}\), where 'n' is the total number of items, 'x' is the number of items being chosen, and '!' denotes a factorial. The factorial function, symbolized by an exclamation mark, indicates the product of all positive integers up to a given number.
Factorials in Probability
Factorials play a key role in probability, especially when evaluating the number of different ways things can be arranged or combined. A factorial, represented by the symbol \(n!\), is the product of all positive integers less than or equal to \(n\). For instance, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\).

In probability, factorials are used to determine the number of possible outcomes. For example, in our exercise, to find out how many different ways we can select 2 successes from 8 trials, we use the factorial function as part of the combination formula to calculate \(C_8^2\).

The calculation of large factorials can be simplified using a calculator or computer software, as they can grow very large quite quickly. Most importantly, the concept of 0! is defined to be 1, which can be useful in calculating combinations and permutations where all items are chosen or none are.
Evaluating Expressions in Statistics
Evaluating expressions is a fundamental skill in statistics, where it often involves handling factorials, powers, and coefficients. In the context of the binomial probability, as in our exercise, the expression represents the probability of getting a certain number of successes \(x\) in a given number of trials \(n\), with a success probability \(p\) and failure probability \(q = 1 - p\).

To accurately evaluate these expressions, you need to perform several steps. First, calculate the necessary combinations to determine the number of ways to achieve \(x\) successes. Then, raise the probabilities to the respective powers of successes and failures. Last, multiply the combination by the calculated probabilities.

A sound understanding of this process is essential for correctly interpreting statistical data and conducting various probability-related calculations. Remember that precision is crucial, as small errors in calculation can lead to incorrect conclusions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A CEO is considering buying an insurance policy to cover possible losses incurred by marketing a new product. If the product is a complete failure, a loss of \(\$ 800,000\) would be incurred; if it is only moderately successful, a loss of \(\$ 250,000\) would be incurred. Insurance actuaries have determined that the probabilities that the product will be a failure or only moderately successful are .01 and \(.05,\) respectively. Assuming that the \(\mathrm{CEO}\) is willing to ignore all other possible losses, what premium should the insurance company charge for a policy in order to break even?

Bad Wiring Improperly wired control panels were mistakenly installed on two of eight large automated machine tools. It is uncertain which of the machine tools have the defective panels, and a sample of four tools is randomly chosen for inspection. What is the probability that the sample will include no defective panels? Both defective panels?

Let \(x\) be a hypergeometric random variable with \(N=15, n=3,\) and \(M=4\). Use this information to answer the questions in Exercises 14-17. Calculate \(p(0), p(1), p(2),\) and \(p(3)\)

A candy dish contains five brown and three red M&Ms. A child selects three M&Ms without checking the colors. Use this information to answer the questions in Exercises \(18-21 .\) What is the probability that the M&Ms are all red?

You can insure a \(\$ 50,000\) diamond for its total value by paying a premium of \(D\) dollars. If the probability of loss in a given year is estimated to be .01, what premium should the insurance company charge if it wants the expected gain to equal \(\$ 1000 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.