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Use the probability distribution for the random variable \(x\) to answer the questions in Exercises 12-16. $$\begin{array}{l|rrrrrr}x & 0 & 1 & 2 & 3 & 4 & 5 \\\\\hline p(x) & .1 & .3 & .4 & .1 & ? & .05\end{array}$$ $$ \text { Find } p(4) $$

Short Answer

Expert verified
Answer: \(p(4) = 0.05\)

Step by step solution

01

Understand the properties of a probability distribution

Recall that in a probability distribution, the sum of the probabilities for all possible values of the random variable must equal 1. In this case, we have a discrete distribution with values of \(x = 0,1,2,3,4,5\). We are given the probabilities for all values except \(x=4\), and we need to find \(p(4)\).
02

Calculate the sum of given probabilities

First, we need to add up the probabilities given in the table for \(x=0,1,2,3,5\). This helps us in finding how much probability is still left for \(x=4\). So, we have: $$ p(0)+p(1)+p(2)+p(3)+p(5) = 0.1 + 0.3 + 0.4 + 0.1 + 0.05 $$
03

Compute the sum

Now, compute the sum: $$ 0.1 + 0.3 + 0.4 + 0.1 + 0.05 = 0.95 $$ So, the sum of the given probabilities is \(0.95\).
04

Find the missing probability \(p(4)\)

We need the sum of all probabilities to be equal to 1. Since we have found the sum of the given probabilities to be 0.95, we can find the missing probability by subtracting the sum from 1: $$ p(4) = 1 - (p(0)+p(1)+p(2)+p(3)+p(5)) $$ Substitute the sum which we computed earlier: $$ p(4) = 1 - 0.95 $$
05

Calculate the final result

Calculate the value of \(p(4)\): $$ p(4) = 0.05 $$ So, the missing probability \(p(4)\) is \(0.05\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Distribution
When we talk about probability, a discrete distribution comes into play when we are dealing with a countable number of possible outcomes. Think of it as a list where you can count each outcome on your fingers, like the number of heads in a series of coin flips or the roll of a die.

In this context, each possible outcome is assigned a specific probability, which is a number between 0 and 1, with the total probability summing up to 1. This is akin to saying that something will definitely happen, but each individual outcome has its own chance of occurring.

For instance, let's imagine you have a bag with differently colored marbles. If you have a finite number of colored marbles and you pick one at random, the probability distribution of picking each color is discrete—you can list out all the possibilities and their associated probabilities.
Random Variable
When dealing with probability distributions, the term random variable is essential. Think of it as a placeholder or a label for the outcomes of a random phenomenon. For example, if you're tossing a coin, you could have a random variable, say 'X', which represents the outcome, such as 'X = 0' for tails and 'X = 1' for heads.

A random variable can take on different values with certain probabilities, and in our context, it's what we call 'discrete.' That's because the possible values of 'X' form a finite or countable set, just like in the textbook exercise where the random variable 'x' could be one of the countable numbers from 0 to 5, representing something that we're measuring, counting, or keeping track of.
Probability Calculation
When you want to find out the likelihood of something happening, you engage in a probability calculation. It involves math, but not just any math—the kind that deals with chance and uncertainty. You look at all the possible outcomes, determine the chances of each happening, and then add up those chances to figure out the overall probability of an event.

In our exercise scenario, the probability distribution table already gives you some of the probabilities. Your job is to use those numbers to find the missing piece of the puzzle. By adding up the probabilities you know and subtracting from 1 (which represents absolute certainty), you can find the probability of the one missing outcome. So, if the sum of the known probabilities is less than 1, the difference gives you the probability of the missing outcome—that's the part of the pie that's not yet accounted for!

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Most popular questions from this chapter

Use Table 1 in Appendix I to evaluate the following probabilities for \(n=6\) and \(p=.8\) : a. \(P(x \geq 4)\) b. \(P(x=2)\) c. \(P(x<2)\) d. \(P(x>1)\) Verify these answers using the values of \(p(x)\) calculated in Exercise 27 .

Explain why \(x\) is or is not a binomial random variable. (Hint: compare the characteristics of this experiment with those of a binomial experiment given in this section.) If the experiment is binomial, give the value of \(n\) and \(p\), if possible. A meteorologist in Chicago recorded \(x\), the number of days of rain during a 30 -day period.

Car color preferences change over the years and according to the particular model that the customer selects. In a recent year, suppose that \(10 \%\) of all luxury cars sold were black. If 25 cars of that year and type are randomly selected, find the following probabilities: a. At least five cars are black. b. At most six cars are black. c. More than four cars are black. d. Exactly four cars are black. e. Between three and five cars (inclusive) are black. f. More than 20 cars are not black.

Voter Registration A city ward consists of 200 registered voters of whom 125 are registered Republicans and 75 are registered with other parties. On voting day, \(n=10\) people are selected at random for an exit poll in this ward. a. What is the probability distribution, \(p(x),\) for \(x,\) the number of Republicans in the poll? b. Find \(p(10)\). c. Find \(p(0)\).

Use the formula for the binomial probability distribution to calculate the values of \(p(x)\) and construct the probability histogram for \(x\) when \(n=6\) and \(p=.2\). [HINT: Calculate \(P(x=k\) ) for seven different values of \(k\).

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