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Let \(x\) be a binomial random variable with \(n=7\) and \(p=.5 .\) Find the values of the quantities in Exercises \(11-15 .\) $$ P(x=4) $$

Short Answer

Expert verified
Answer: The probability is approximately 0.2734.

Step by step solution

01

Identify the parameters

In this case, n=7, p=0.5, and we need to find P(x=4).
02

Calculate the binomial coefficient

We need to find the binomial coefficient, which is: $$ \binom{n}{k} = \frac{n!}{k!(n-k)!} $$ For our case, n=7 and k=4, so the binomial coefficient is: $$ \binom{7}{4} = \frac{7!}{4!(7-4)!} = \frac{7!}{4!3!} = \frac{7\times6\times5}{3\times2\times1} = 35 $$
03

Apply the binomial probability formula

Now we can use the binomial probability formula: $$ P(x=4) = \binom{7}{4} (0.5)^4 (1-0.5)^{7-4} = 35 \times (0.5)^4 \times (0.5)^{3} $$
04

Calculate the probability

Evaluate the expression to get the probability: $$ P(x=4) = 35 \times (0.5)^4 \times (0.5)^{3} = 35 \times 0.0625 \times 0.125 = 0.2734375 $$ So the probability P(x=4) is approximately 0.2734.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Random Variable
A binomial random variable is a specific type of discrete random variable that counts the number of successes in a fixed number of independent trials of a binary experiment.

A binary experiment is one where there are only two possible outcomes: either a 'success' or a 'failure'. For instance, flipping a coin results in two possible outcomes - heads or tails. If we designate 'heads' as a success, then flipping a coin multiple times can be seen as a series of binary experiments.

The two parameters that define a binomial random variable are:
  • The number of trials, denoted as 'n'.
  • The probability of success in a single trial, denoted as 'p'.
In the exercise provided, we were dealing with a binomial random variable with 7 trials (flips), and the probability of success ('head' in this case) in each trial was 0.5, which is common in a fair coin flip.
Binomial Coefficient
The binomial coefficient, often read as 'n choose k', is a fundamental component in combinatorics and signifies the number of ways to choose 'k' successes out of 'n' trials, without considering the order.

Mathematically, the binomial coefficient is denoted by:
\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]
where \(n!\) (n factorial) is the product of all positive integers up to 'n', \(k!\) is the factorial of 'k', and \((n-k)!\) is the factorial of the difference between 'n' and 'k'.

In the context of our exercise, the binomial coefficient calculated as \(\binom{7}{4}\) determines the number of ways we can achieve exactly 4 heads (successes) in 7 coin tosses (trials). This calculation aids in the evaluation of the probability for the binomial random variable 'x' when x equals 4.
Probability Formula
The probability formula for a binomial distribution allows you to calculate the likelihood of obtaining a specific number of successes in a fixed number of trials, given the probability of success on a single trial.

The general binomial probability formula is given by:
\[P(x=k) = \binom{n}{k} p^k (1-p)^{(n-k)}\]
Here, \(P(x=k)\) is the probability of getting exactly 'k' successes in 'n' trials. \(p^k\) represents the probability of success raised to the number of successes, and \((1-p)^{(n-k)}\) represents the probability of failure raised to the number of failures. As applied in the exercise solution, through this formula, we calculated the probability of getting 4 heads out of 7 coin tosses, interpreting the heads as successes with a probability of 0.5 each.

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Most popular questions from this chapter

Explain why \(x\) is or is not a binomial random variable. (Hint: compare the characteristics of this experiment with those of a binomial experiment given in this section.) If the experiment is binomial, give the value of \(n\) and \(p\), if possible. Two balls are randomly selected with replacement from a jar that contains three red and two white balls. The number \(x\) of red balls is recorded.

Suppose that 1 out of every 10 homeowners in the state of California has invested in earthquake insurance. If 15 homeowners are randomly chosen to be interviewed, a. What is the probability that at least one had earthquake insurance? b. What is the probability that four or more have earthquake insurance? c. Within what limits would you expect the number of homeowners insured against earthquakes to fall?

Explain why \(x\) is or is not a binomial random variable. (Hint: compare the characteristics of this experiment with those of a binomial experiment given in this section.) If the experiment is binomial, give the value of \(n\) and \(p\), if possible. A meteorologist in Chicago recorded \(x\), the number of days of rain during a 30 -day period.

If a drop of water is examined under a microscope, the number \(x\) of a specific type of bacteria present has been found to have a Poisson probability distribution. Suppose the maximum permissible count per water specimen for this type of bacteria is five. If the mean count for your water supply is two and you test a single specimen, is it likely that the count will exceed the maximum permissible count? Explain.

The number of births at the local hospital has a Poisson distribution with an average of 6 per day. a. What is the probability distribution for the daily number of births at this hospital? b. What is the probability distribution for the number of hourly births? c. What is the probability that there are fewer than 3 births in a given hour? d. Within what interval would you expect to find the number of hourly births at least \(89 \%\) of the time?

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