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A sampling of political candidates- 200 randomly chosen from the West and 200 from the East-was classified according to whether the candidate received backing by a national labor union and whether the candidate won. In the West, 120 winners had union backing, and in the East, 142 winners were backed by a national union. Find a \(95 \%\) confidence interval for the difference between the proportions of union-backed winners in the West versus the East. Interpret this interval.

Short Answer

Expert verified
Answer: The 95% confidence interval for the difference between the proportions of union-backed winners in the Western region compared to the Eastern region is (-0.221, 0.001). Since the interval includes zero, we cannot conclude that there is a significant difference between the proportions of union-backed winners in the two regions.

Step by step solution

01

Calculate the sample proportions

Calculate the proportions of union-backed winners in the West and East samples: $$ \hat{p}_1 = \frac{x_1}{n_1} = \frac{120}{200} = 0.6 \\ \hat{p}_2 = \frac{x_2}{n_2} = \frac{142}{200} = 0.71 $$
02

Find the difference in sample proportions

Calculate the difference in sample proportions: $$ \hat{p}_1 - \hat{p}_2 = 0.6 - 0.71 = -0.11 $$
03

Calculate the overall sample proportion

Compute the overall sample proportion, denoted by \(\hat{p}\): $$ \hat{p} = \frac{x_1 + x_2}{n_1 + n_2} = \frac{120 + 142}{200 + 200} = \frac{262}{400} = 0.655 $$
04

Calculate the standard error of the difference

Compute the standard error for the difference in proportions: $$ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n_1} + \frac{\hat{p}(1 - \hat{p})}{n_2}} = \sqrt{\frac{0.655(1 - 0.655)}{200} + \frac{0.655(1 - 0.655)}{200}} = 0.0566 $$
05

Calculate the margin of error

Calculate the margin of error using the critical value for a 95% confidence interval (z = 1.96) and the standard error: $$ ME = z \times SE = 1.96 \times 0.0566 = 0.111 $$
06

Calculate the 95% confidence interval

Find the 95% confidence interval for the difference between the proportions of union-backed winners in the West versus the East by adding and subtracting the margin of error from the difference in sample proportions: $$ CI = (\hat{p}_1 - \hat{p}_2) \pm ME = -0.11 \pm 0.111 = (-0.221, 0.001) $$
07

Interpret the Confidence Interval

The 95% confidence interval for the difference between the proportions of union-backed winners in the West and the East is (-0.221, 0.001). This means that we are 95% confident that the proportion of union-backed winners in the West is between 0.221 less and 0.001 more than the proportion of union-backed winners in the East. Since the interval includes zero, we cannot conclude that there is a significant difference between the proportions of union-backed winners in the West and the East.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference in Proportions
In statistics, when we talk about the difference in proportions, we are comparing two different groups to see if there is a significant change or difference between them. In our exercise, we have two groups of political candidates: one from the West and one from the East. By looking at the proportion of candidates backed by unions in each group, we can potentially detect trends or evaluate union impact.

The calculation involves computing the proportion of interest (here, those with union backing) for each group separately. For example, the proportion of backed winners in the West is calculated as \[ \hat{p}_1 = \frac{120}{200} = 0.6 \] while in the East, it is \[ \hat{p}_2 = \frac{142}{200} = 0.71.\] By finding the difference \( \hat{p}_1 - \hat{p}_2 = 0.6 - 0.71 = -0.11 \), we can see that, on average, a lower proportion of candidates in the West have union backing compared to the East.
Hypothesis Testing
Hypothesis testing is a core aspect of statistics that helps us decide whether to accept or reject a hypothesis based on sample data. When comparing proportions from two groups, we often set up a null hypothesis, typically stating there is no difference in proportions between the groups.

The process follows these steps:
  • Define the null and alternative hypotheses. For instance, \( H_0: p_1 = p_2 \) states there is no difference, and \( H_a: p_1 eq p_2 \) indicates a difference exists.
  • Compute the test statistic based on the sample data.
  • Determine if this statistic falls in the critical region, using a significance level (commonly 0.05 for 95% confidence).
  • Conclude if the result is significant enough to reject the null hypothesis.
In our example, after calculating the confidence interval that includes zero, we fail to reject the null hypothesis, suggesting that there is no statistically significant difference in the union backing between the West and East candidates.
Standard Error
Standard error is a vital concept in statistics as it gauges the extent to which a sample proportion may differ from the true population proportion. When dealing with sample data, like the union backing of candidates, the standard error helps provide a sense of how much sample proportions fluctuate due to randomness.

To calculate the standard error for the difference in proportions, we use the formula: \[SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n_1} + \frac{\hat{p}(1 - \hat{p})}{n_2} }\] where \( \hat{p} \) is the pooled proportion, calculated as \( \frac{x_1 + x_2}{n_1 + n_2} \). The standard error we computed for this scenario was 0.0566. This gives us a sense of measurement accuracy, determining the estimates' precision, with smaller standard errors indicating more precise measurements.
Margin of Error
Margin of error provides a range around a sample estimate, giving an idea of how much one can expect the sample estimate to vary from the true population value. It's an essential part of constructing confidence intervals.

In this instance, the margin of error is determined by multiplying the standard error by the critical value from the standard normal distribution (z-score): \[ ME = z \times SE = 1.96 \times 0.0566 = 0.111 \] For a 95% confidence interval, a z-score of 1.96 is used.

Adding and subtracting this margin of error from the observed difference in proportions, we derive the confidence interval.

For our example with a margin of error of 0.111, the interval from -0.221 to 0.001 tells us we are 95% confident that the true difference lies within this range, showing a noteworthy statistical concept that reflects possible real-world variations in data.

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Most popular questions from this chapter

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