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Consider a binomial experiment with \(n=20\) and \(p=.4 .\) Calculate \(P(x \geq 10)\) using each of these methods: a. Table 1 in Appendix I b. The normal approximation to the binomial probability distribution

Short Answer

Expert verified
Answer: The probability of \(P(x \geq 10)\) is approximately 0.2483 using the normal approximation.

Step by step solution

01

Define the parameters of the binomial distribution

For our binomial experiment, we have \(n=20\) trials and \(p=0.4\) probability of success.
02

Calculate the probabilities using the table

To find \(P(x \geq 10)\), we need to look up the probabilities in the table for \(x = 10, 11, 12, \dots, 20\). Add up these probabilities to get the final probability.
03

Find the probability \(P(x \geq 10)\) using the table

Using the table, we find the following probabilities for \(x=10, 11, 12, \dots, 20\) and add them up: \(P(x \geq 10) = P(10) + P(11) + P(12) + \dots + P(20)\). #Method b: Using the normal approximation to the binomial distribution#
04

Calculate the mean and standard deviation

The mean and standard deviation of a binomial distribution are given by: Mean: \(\mu = np\) Standard deviation: \(\sigma = \sqrt{np(1-p)}\) In our case: \(\mu = 20 * 0.4 = 8\) \(\sigma = \sqrt{20 * 0.4 * (1-0.4)} = \sqrt{4.8} \approx 2.19\)
05

Convert the problem into a normal distribution problem

To approximate the binomial distribution using a normal distribution, we can use the Z-score as follows: \(Z = \frac{x - \mu}{\sigma}\) We want to find \(P(x \geq 10)\). Since the normal distribution is continuous, we can use the continuity correction and change \(10\) to \(9.5\). So we want to find \(P(x \geq 9.5)\) in the normal distribution.
06

Calculate the Z-score

Using the continuity correction, we can calculate the Z-score for \(x=9.5\): \(Z = \frac{9.5 - 8}{2.19} \approx 0.68\)
07

Use the standard normal table to find the probability

Using the standard normal table, we find the probability for \(Z=0.68\): \(P(Z \leq 0.68) \approx 0.7517\) Since we want to find \(P(x \geq 9.5)\), we have to subtract the probability from \(1\): \(P(x \geq 9.5) = 1 - P(Z \leq 0.68) = 1 - 0.7517 \approx 0.2483\) Now we have calculated \(P(x \geq 10)\) using both methods a and b. Comparing the probabilities obtained, we can see that the normal approximation is a good estimation for the binomial probability in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Approximation
The normal approximation is a useful method for estimating probabilities of a binomial distribution, especially when calculating probabilities by hand can become cumbersome. In a binomial experiment where the number of trials is large, the distribution of possible outcomes gets closer to that of a normal distribution. This is known as the Central Limit Theorem, which allows us to use the more manageable normal distribution to approximate binomial probabilities.

To use the normal approximation effectively, certain criteria should be met:
  • The number of trials, denoted by \(n\), should be large enough (typically \(n > 30\) is a rule of thumb, but it can work even with \(n\) as low as 20 when \(p\) is not too close to 0 or 1).
  • The probability of success, \(p\), should not be too extreme (not too close to 0 or 1).
In the given problem with \(n=20\) and \(p=0.4\), we applied normal approximation by first calculating the mean \(\mu\) and the standard deviation \(\sigma\) of the binomial distribution. These serve as the parameters for conversion to a normal problem, which simplifies the process of finding probabilities.
Probability Calculation
To calculate the probability using the normal approximation, a sequence of steps helps. Begin by defining the mean and standard deviation of the equivalent normal distribution:
- The mean \(\mu\) is calculated as \(np\).- The standard deviation \(\sigma\) is \(\sqrt{np(1-p)}\).

For this specific problem:
  • \(\mu = 20 \times 0.4 = 8\)
  • \(\sigma = \sqrt{20 \times 0.4 \times (1-0.4)} \approx 2.19\)
These derived parameters enable the conversion of binomial problems into a framework that utilizes the normal distribution, employing Z-scores.

Next, calculate the Z-score using the formula:\[Z = \frac{x - \mu}{\sigma}\]This standardizes the value, transforming it into a metric that can reference a standard normal distribution table and from which probabilities are accessible.
Continuity Correction
A particularly important part of using a normal approximation for a discrete binomial distribution is applying the continuity correction. Since the binomial distribution is discrete (distinct whole numbers), but the normal distribution is continuous (a range of values), we introduce a correction to improve approximation accuracy.

This correction involves adjusting our target probability by 0.5 in the direction needed for the inequality:
- To approximate \(P(x \geq k)\), we adjust to \(P(x \geq k - 0.5)\).

In the original example, when finding \(P(x \geq 10)\), you actually calculate \(P(x \geq 9.5)\) using the normal distribution. This shift accounts for the inclusion of values that lie between integer point thresholds, resulting in a more precise prediction.

Utilizing the standard normal table after adjusting for continuity allows us to determine the associated probability more accurately and reflects better alignment with the original discrete scenario.

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