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A population can be divided into two subgroups that occur with probabilities \(60 \%\) and \(40 \%\), respectively. An event \(A\) occurs \(30 \%\) of the time in the first subgroup and \(50 \%\) of the time in the second subgroup. What is the unconditional probability of the event \(A\), regardless of which subgroup it comes from?

Short Answer

Expert verified
Answer: The unconditional probability of event A occurring, regardless of which subgroup it comes from, is 0.38 or 38%.

Step by step solution

01

Identify the given probabilities

Let's denote the two subgroups as events \(B_1\) and \(B_2\). The given probabilities are:$$ P(B_1) = 0.6 (60 \%) $$ $$ P(B_2) = 0.4 (40 \%) $$ $$ P(A | B_1) = 0.3 (30 \%) $$ $$ P(A | B_2) = 0.5 (50 \%) $$Here, \(P(A|B_1)\) represents the probability of event A occurring given that event \(B_1\) has occurred, and \(P(A|B_2)\) represents the probability of event A occurring given that event \(B_2\) has occurred.
02

Apply the Law of Total Probability

According to the Law of Total Probability, the unconditional probability of event A can be calculated as follows: $$ P(A) = P(A|B_1) \cdot P(B_1) + P(A|B_2) \cdot P(B_2) $$Substituting the given probabilities into the formula, we have: $$ P (A) = 0.3 \cdot 0.6 + 0.5 \cdot 0.4 $$
03

Calculate the unconditional probability of A

Now we can evaluate the expression for the unconditional probability: $$ P(A) = 0.18 + 0.20 $$ $$ P(A) = 0.38 $$The unconditional probability of event A occurring, regardless of which subgroup it comes from, is equal to \(0.38\) or \(38 \%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability helps us to understand the likelihood of an event occurring, given that another event has already occurred. Let's break it down simply. When we say "given," we are talking about a condition that is already met. For example, if you only eat ice cream when it's sunny, the chance of you eating ice cream depends on it being sunny. That's conditional probability. It allows us to update our predictions based on new information or a specific situation. In mathematical terms, if we have two events, say Event A (eating ice cream) and Event B (sunny day), the conditional probability of Event A given Event B is denoted as \(P(A|B)\). This represents the probability of Event A happening provided Event B has indeed occurred.
  • This concept is integral in everyday situations, where conditions or information influence the chance of events.
  • It forms the foundation for more complex probability topics, like the law of total probability and Bayes' theorem.
Unconditional Probability
Unconditional probability, also known as marginal probability, evaluates the chance of an event happening without any conditions or additional information. It's like asking, "What's the chance of rain today?" without looking at the weather forecast. This form of probability ignores any prior circumstances, revealing the broader or overall likelihood of an event. Using our previous example, if we want to know the probability of eating ice cream without checking the weather, we're dealing with unconditional probability. In mathematical terms, for an event A, it's simply \(P(A)\), which reflects the chance of A occurring in the entire probability space.
  • Unconditional probability is vital for general predictions or when detailed conditional information is unavailable.
  • It's often calculated using available data or sometimes derived from conditional probabilities using rules like the law of total probability.
Probability Theory
Probability theory is an essential branch of mathematics that deals with quantifying uncertainty. It's like having a set of rules or guidelines to determine the likelihood of different outcomes. This theory builds the groundwork for reasoning in everyday decision-making and across various fields like statistics, finance, and science. Key components of probability theory include:
  • Probability Space: The entire "universe" of possible outcomes for a given experiment or situation.
  • Random Variables: Variables that can take different values based on the outcomes of chance.
  • Events: These are specific outcomes or groups of outcomes we are interested in.
  • Probability Measures: Functions that assign a likelihood to events within the probability space.
Probability isn't always intuitive, but probability theory provides frameworks and theorems, like the law of total probability, to calculate and understand it. By applying these principles, one can make informed predictions and decisions even in uncertain situations.

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Most popular questions from this chapter

A smoke-detector system uses two devices, \(A\) and \(B\). If smoke is present, the probability that it will be detected by device \(A\) is .95 by device \(B, .98 ;\) and by both devices, .94 a. If smoke is present, find the probability that the smoke will be detected by device \(A\) or device \(B\) or both devices. b. Find the probability that the smoke will not be detected.

A heavy-equipment salesman can contact either one or two customers per day with probabilities \(1 / 3\) and \(2 / 3,\) respectively. Each contact will result in either no sale or a \(\$ 50,000\) sale with probabilities \(9 / 10\) and \(1 / 10,\) respectively. What is the expected value of his daily sales?

Under the "no pass, no play" rule for athletes, an athlete who fails a course is disqualified from participating in sports activities during the next grading period. Suppose the probability that an athlete who has not previously been disqualified will be disqualified is .15 and the probability that an athlete who has been disqualified will be disqualified again in the next time period is \(.5 .\) If \(30 \%\) of the athletes have been disqualified before, what is the unconditional probability that an athlete will be disqualified during the next grading period?

A random variable \(x\) has this probability distribution: $$\begin{array}{l|llllll}x & 0 & 1 & 2 & 3 & 4 & 5 \\\\\hline p(x) & .1 & .3 & .4 & .1 & ? & .05\end{array}$$ a. Find \(p(4)\). b. Construct a probability histogram to describe \(p(x)\). c. Find \(\mu, \sigma^{2},\) and \(\sigma\). d. Locate the interval \(\mu \pm 2 \sigma\) on the \(x\) -axis of the histogram. What is the probability that \(x\) will fall into this interval? e. If you were to select a very large number of values of \(x\) from the population, would most fall into the interval \(\mu \pm 2 \sigma\) ? Explain.

From experience, a shipping company knows that the cost of delivering a small package within 24 hours is \(\$ 14.80 .\) The company charges \(\$ 15.50\) for shipment but guarantees to refund the charge if delivery is not made within 24 hours. If the company fails to deliver only \(2 \%\) of its packages within the 24 -hour period, what is the expected gain per package?

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