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A smoke-detector system uses two devices, \(A\) and \(B\). If smoke is present, the probability that it will be detected by device \(A\) is .95 by device \(B, .98 ;\) and by both devices, .94 a. If smoke is present, find the probability that the smoke will be detected by device \(A\) or device \(B\) or both devices. b. Find the probability that the smoke will not be detected.

Short Answer

Expert verified
Answer: The probability that smoke will be detected by either device A or device B or both devices is 0.99, and the probability that smoke won't be detected at all is 0.01.

Step by step solution

01

Recall the formula for probability of the union of two events.

To find the probability that either of two events occurs, we can use the formula: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where A and B are the events, and P(X) represents the probability of event X occurring.
02

Use the given probabilities and formula.

We are given the following probabilities: - P(A) = 0.95 (Probability of smoke being detected by device A) - P(B) = 0.98 (Probability of smoke being detected by device B) - P(A ∩ B) = 0.94 (Probability of smoke being detected by both devices) We'll use these probabilities to find the probability of smoke being detected by device A or device B or both devices: P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
03

Calculate the probability.

Now, plug in the given probabilities into the formula: P(A ∪ B) = 0.95 + 0.98 - 0.94 P(A ∪ B) = 0.99 So, the probability that smoke will be detected by device A or device B or both devices is 0.99.
04

Finding the probability of smoke not being detected.

To find the probability that smoke will not be detected, we'll subtract the probability that smoke will be detected by either device or both devices from 1: P(Not Detected) = 1 - P(A ∪ B) P(Not Detected) = 1 - 0.99 P(Not Detected) = 0.01 So, the probability that smoke will not be detected is 0.01. To summarize: a. The probability that the smoke will be detected by device A or device B or both devices is 0.99. b. The probability that the smoke will not be detected is 0.01.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Union of Events
In probability theory, the union of two events relates to the concept of either one or both of the events occurring. When considering two events, say Event A and Event B, the probability of either A or B happening is a fundamental concept captured by the union of the two events. This can be calculated using the formula:\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]This formula accounts for the probabilities of each event individually plus the probability that both events occur, which is subtracted to avoid double-counting the overlap.
If we consider the scenario of smoke detectors, where the probability of smoke being detected by Device A is 0.95 and by Device B is 0.98, and by both is 0.94, we can substitute these values into the formula to find the probability of detection by either or both devices. This gives us:- \( P(A \cup B) = 0.95 + 0.98 - 0.94 = 0.99 \)So, there's a 99% chance that smoke will be detected by one or both devices. This illustrates how the union of events works to combine overlapping possibilities into a single probability measure.
Complement Rule
The complement rule is a handy tool in probability that helps us find the probability of an event not occurring. It is based on the idea that the total probability of all possible outcomes of a trial must equal 1.
For any event A, the probability of the complement of A (which means A does not occur) is given by:\[ P(A^c) = 1 - P(A) \]In our smoke detector example, once we know the probability that the smoke will be detected by at least one device is 0.99, the complement rule can help us find the probability that the smoke goes undetected. Here's the straightforward calculation:- \( P(\text{Not Detected}) = 1 - P(A \cup B) = 1 - 0.99 = 0.01 \)That means there is only a 1% chance that the smoke will not be detected by either device. The complement rule is especially useful because it allows us to easily flip between known and unknown probabilities by considering all possible scenarios.
Conditional Probability
Conditional probability allows us to calculate the probability of an event occurring given that another event has occurred. Although not directly used in the provided example, it's crucial to understanding dependent events.
Conditional probability is denoted as \( P(A | B) \), which is the probability of event A occurring given that event B has already happened. The conditional probability formula is expressed as:\[ P(A | B) = \frac{P(A \cap B)}{P(B)} \]This concept is critical when events are not independent, and understanding it allows you to adjust expectations based on given conditions. For instance, if we were to question the probability of detecting smoke with Device A, given that Device B has detected smoke, conditional probability would provide the necessary framework.In situations involving multiple interdependent events, using conditional probability can often unveil more complex relationships and dependencies that aren't immediately apparent, enhancing analytical insights into probabilistic scenarios.

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Most popular questions from this chapter

Two cold tablets are unintentionally placed in a box containing two aspirin tablets. The four tablets are identical in appearance. One tablet is selected at random from the box and is swallowed by the first patient. A tablet is then selected at random from the three remaining tablets and is swallowed by the second patient. Define the following events as specific collections of simple events: a. The sample space \(S\) b. The event \(A\) that the first patient obtained a cold tablet c. The event \(B\) that exactly one of the two patients obtained a cold tablet d. The event \(C\) that neither patient obtained a cold tablet

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