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Colored Contacts Refer to Exercise \(9.37 .\) Contact lenses, worn by about 26 million Americans, come in many styles and colors. Most Americans wear soft lenses, with the most popular colors being the blue varieties \((25 \%),\) followed by greens \((24 \%),\) and then hazel or brown. A random sample of 80 tinted contact lens wearers was checked for the color of their lenses. Of these people, 22 wore blue lenses and only 15 wore green lenses. a. Do the sample data provide sufficient evidence to indicate that the proportion of tinted contact lens wearers who wear blue lenses is different from \(25 \% ?\) Use \(\alpha=.05 .\) b. Do the sample data provide sufficient evidence to indicate that the proportion of tinted contact lens wearers who wear green lenses is different from \(24 \% ?\) Use \(\alpha=.05\) c. Is there any reason to conduct a one-tailed test for either part a or b? Explain.

Short Answer

Expert verified
If so, provide the specific p-value evidence for each color. Additionally, explain if there is a reason to conduct a one-tailed test for any part of the exercise.

Step by step solution

01

State the hypotheses

We want to test the difference between the sample proportion and the stated proportion of 0.25. The null hypothesis (H0): The proportion of people wearing blue lenses is \(25\% (0.25)\). $$H_0: p = 0.25$$ The alternative hypothesis (H1): The proportion of people wearing blue lenses is not \(25\% (0.25)\). $$H_1: p \neq 0.25$$
02

Calculate the test statistic

We will use the z-test to calculate the test statistic. $$z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}$$ Where \(\hat{p}\) is the sample proportion, \(p_0\) is the population proportion, and \(n\) is the sample size. In our case, \(\hat{p}=\frac{22}{80}\), \(p_0=0.25\), and \(n=80\).
03

Find the p-value

Using the z-table or calculator, find the p-value corresponding to the test statistic calculated in Step 2. Since it's a two-tailed test, multiply the p-value by 2.
04

Make a decision

Compare the calculated p-value with the significance level \(\alpha=0.05\). If the p-value is less than \(\alpha\), reject the null hypothesis. If the p-value is greater than \(\alpha\), fail to reject the null hypothesis. #a. Hypothesis test for Green lenses#
05

State the hypotheses

We want to test the difference between the sample proportion and the stated proportion of 24%. The null hypothesis (H0): The proportion of people wearing green lenses is \(24\% (0.24)\). $$H_0: p = 0.24$$ The alternative hypothesis (H1): The proportion of people wearing green lenses is not \(24\% (0.24)\). $$H_1: p \neq 0.24$$
06

Calculate the test statistic

We will use the z-test to calculate the test statistic. $$z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}$$ In our case, \(\hat{p}=\frac{15}{80}\), \(p_0=0.24\), and \(n=80\).
07

Find the p-value

Using the z-table or calculator, find the p-value corresponding to the test statistic calculated in Step 2. Since it's a two-tailed test, multiply the p-value by 2.
08

Make a decision

Compare the calculated p-value with the significance level \(\alpha=0.05\). If the p-value is less than \(\alpha\), reject the null hypothesis. If the p-value is greater than \(\alpha\), fail to reject the null hypothesis. #c. Should we conduct a one-tailed test for either part a or b?# Since we are testing if the proportions are different, and we do not have any information favoring one direction over the other, we should not conduct a one-tailed test for either part a or b. The two-tailed test is appropriate for this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Testing
Proportion testing is used to assess whether the proportion of a certain characteristic in a population matches a specific value. This kind of test can tell us if the reality is significantly different from what we expect based on a hypothesis. For example, in a sample of contact lens wearers, we might want to know if the proportion who prefer blue lenses differs from 25%.
In hypothesis testing for proportions, we follow a structured approach:
  • Set up the null and alternate hypotheses, where the null hypothesis usually states that there is no difference (e.g., the proportion is 25%).
  • Choose a significance level, often denoted by \(\alpha\), like 0.05, which determines the cutoff for deciding whether an observed effect is statistically surprising.
  • Collect the sample data and calculate the sample proportion, which is done by dividing the number of occurrences (such as people wearing blue lenses) by the total sample size.
  • Use this sample proportion to calculate a test statistic that helps determine if the difference you see is due to random chance.
  • Finally, make a decision by comparing the p-value associated with the test statistic against the significance level.
These steps help test whether the observed proportion significantly deviates from the claimed population proportion, based on the sample data.
Z-test
The Z-test is a statistical method used to test hypotheses about the population mean when the sample size is large, or when the population variance is known. In the context of proportion testing, it helps us determine how far the sample proportion is from the hypothesized population proportion stated in the null hypothesis, using standard deviations as a measure.
The formula for the Z-test statistic in proportion testing is:\[z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}\]where:
  • \(\hat{p}\) is the sample proportion,
  • \(p_0\) is the population proportion under the null hypothesis, and
  • \(n\) is the sample size.
Once we calculate the Z-test statistic, we can find its corresponding p-value, which tells us how likely it is to observe a sample proportion as extreme as ours, assuming the null hypothesis is true. This helps in making informed decisions about rejecting or not rejecting the null hypothesis. The Z-test is very useful because it tells us in standardized terms (z-scores) how far away our sample finding is from what's expected.
Two-tailed Test
A two-tailed test in hypothesis testing is used when we are interested in deviations on both sides of the hypothesized population parameter. Essentially, it checks whether the observed effect can be either significantly more or significantly less than the expected value.
In the context of contact lenses, if we test whether the proportion of lens wearers choosing a specific color is different from a set percentage, we're interested in any difference, not just an increase or a decrease. Hence, a two-tailed test is appropriate.
Steps in a two-tailed test include:
  • Establishing your null hypothesis as a statement of no effect (e.g., the proportion is exactly 25%) and your alternative hypothesis as the proportion being different (not equal to 25%).
  • Calculating the test statistic and the corresponding p-value. Because any significant deviation, regardless of direction, is important, you multiply the p-value by two to account for both "tails" of the distribution.
  • Making a decision about the null hypothesis based on whether the two-tailed p-value is below the significance level.
Two-tailed tests are common when we do not have prior predictions about the direction of the effect, making them a fundamental technique in hypothesis testing.

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Most popular questions from this chapter

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