/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 Suppose you wish to estimate the... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose you wish to estimate the mean \(\mathrm{pH}\) of rainfalls in an area that suffers heavy pollution due to the discharge of smoke from a power plant. You know that \(\sigma\) is in the neighborhood of \(.5 \mathrm{pH},\) and you wish your estimate to lie within .1 of \(\mu\), with a probability near .95. Approximately how many rainfalls must be included in your sample (one pH reading per rainfall)? Would it be valid to select all of your water specimens from a single rainfall? Explain.

Short Answer

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Additionally, is selecting all water specimens from a single rainfall a valid approach for this estimation? Answer: The appropriate sample size required is approximately 97 rainfalls. Selecting all water specimens from a single rainfall is not a valid approach as it does not account for the variability among different rainfalls and would lead to biased results. Instead, the sample should be collected from multiple rainfalls to capture the overall mean pH of the rainfalls in the given area.

Step by step solution

01

Understand the problem and identify the given values

We are given: - Standard deviation (σ) ≈ 0.5 pH - Margin of error (E) = 0.1 pH - Confidence level = 95% We need to find the sample size (n).
02

Calculate the required z-score

For a 95% confidence level, we can find the z-score using a standard normal table or calculator. The z-score corresponding to a 95% confidence level is 1.96 (which means that 95% of the data is within 1.96 standard deviations from the mean).
03

Use the formula to calculate the sample size

The formula to calculate the sample size (n) is given by: n = \(\left(\frac{z * \sigma}{E} \right)^2\) where: - n = sample size - z = z-score (1.96 for a 95% confidence level) - σ = standard deviation (0.5 pH) - E = margin of error (0.1 pH) Plugging in the values, we have: n = \(\left(\frac{1.96 * 0.5}{0.1} \right)^2\) Calculating the value, we get: n ≈ 96.04 Since we cannot have a fraction of a sample, we round up to get the smallest whole number of samples larger than this value: n = 97 Hence, we must include approximately 97 rainfalls in our sample.
04

Determine the validity of the single-rainfall specimen selection method

Selecting all water specimens from a single rainfall is not a valid approach because it does not account for the variability among different rainfalls. It would lead to biased results as the sample would not be representative of the population. A proper sample should be collected from multiple rainfalls to capture the overall mean pH of the rainfalls in the given area.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability and Statistics
Probability and statistics form the foundation of data analysis, enabling researchers and statisticians to make sense of data and draw reliable conclusions. Using probability, we can predict the likelihood of any given event occurring, such as rainfall acidity. In this context, statistics help us summarize and interpret the data collected, giving us the tools to estimate the mean pH level of a polluted area's rainfall. Understanding the behavior of data through the lens of probability and statistics allows us to estimate with confidence, being nearly sure that the actual mean pH is close to our estimation.
Confidence Interval
The concept of a confidence interval in statistics is crucial to understanding how precise our estimates are. A confidence interval indicates the range within which the true population parameter, like the mean pH of rainfalls, is expected to lie with a specific probability. It's a way of quantifying the uncertainty in our estimate. When we refer to a 95% confidence interval, we're saying that if we were to take many samples and calculate an interval for each, we would expect approximately 95% of those intervals to contain the true population mean. This does not mean that the true mean has a 95% chance of being in our interval – the true mean is fixed, and our interval either contains it or it does not.
Standard Deviation
Standard deviation is a statistic that measures the dispersion or spread of a set of values. In simple terms, it tells us how much values in a dataset deviate from the average value, or mean. A low standard deviation indicates that the values tend to be close to the mean, while a high standard deviation points to values being spread out over a wider range. In the context of pH levels in rainfalls, a standard deviation of 0.5 suggests that the pH levels cluster reasonably close around the mean. This measurement is essential in the formula for calculating sample size, as it influences how large our sample needs to be to estimate the mean with a desired level of precision and confidence.
Margin of Error
The margin of error plays a critical role in determining how accurate our estimates are. It is the maximum expected difference between the true population parameter and a sample estimate of that parameter. A smaller margin of error means a more precise estimate, but it often requires a larger sample size. In our example, the margin of error of 0.1 pH units signifies that our sample estimate of the mean pH level could be within 0.1 units of the true population mean. Balancing the margin of error with sample size is key to efficient research – too large, and our estimate will be imprecise; too small, and we may need an impractically large sample.

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Most popular questions from this chapter

Smoking and Blood Pressure An experiment was conducted to estimate the effect of smoking on the blood pressure of a group of 35 cigarette smokers. The difference for each participant was obtained by taking the difference in the blood pressure readings at the beginning of the experiment and again five years later. The sample mean increase, measured in millimeters of mercury, was \(\bar{x}=9.7\). The sample standard deviation was \(s=5.8\). Estimate the mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment. Find the margin of error. Describe the population associated with the mean that you have estimated.

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Calculate the margin of error in estimating a binomial proportion for each of the following values of \(n\). Use \(p=.5\) to calculate the standard error of the estimator. a. \(n=30\) b. \(n=100\) c. \(n=400\) d. \(n=1000\)

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