/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 The results of a Newsweek poll c... [FREE SOLUTION] | 91Ó°ÊÓ

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The results of a Newsweek poll concerning views on abortion given in Exercise 7.66 showed that of \(n=1002\) adults, \(39 \%\) favored the "right-to-life" stand, while \(53 \%\) were "pro-choice." The poll reported a margin of error of plus or minus \(3 \%\). a. Construct a \(90 \%\) confidence interval for the proportion of adult Americans who favor the "right-tolife" position. b. Construct a \(90 \%\) confidence interval for the proportion of adult Americans who favor the "pro-choice" position.

Short Answer

Expert verified
Answer: The 90% confidence interval for the Right-to-Life position is between 35.95% and 42.05%, and the 90% confidence interval for the Pro-Choice position is between 49.9% and 56.1%.

Step by step solution

01

Find the sample proportion and critical value for Right-to-Life position

First, we need to determine the sample proportion for the Right-to-Life position, which is 39%. Therefore, \(\hat{p} = 0.39\). We also need the 90% critical value (z-value), which we can look up or calculate as \(z_\frac{\alpha}{2} = 1.645\).
02

Calculate the Right-to-Life Confidence Interval

Now we can use the formula for the confidence interval: \(CI = 0.39 \pm 1.645 \times \sqrt{\frac{0.39(1-0.39)}{1002}}\) Calculate the margin of error: \(1.645 \times \sqrt{\frac{0.39(1-0.39)}{1002}} = 0.0305\) So, the confidence interval for the Right-to-Life position is: \(0.39 \pm 0.0305 = (0.3595, 0.4205)\) This means that we are 90% confident that the true proportion of adult Americans who favor the Right-to-Life position is between 35.95% and 42.05%. #b. Confidence Interval for Pro-Choice Position#
03

Find the sample proportion and critical value for Pro-Choice position

Similar to part a, we need to determine the sample proportion and critical value for the Pro-Choice position. We know that \(\hat{p} = 0.53\) for this position and, again, we have \(z_\frac{\alpha}{2} = 1.645\).
04

Calculate the Pro-Choice Confidence Interval

Using the formula for the confidence interval: \(CI = 0.53 \pm 1.645 \times \sqrt{\frac{0.53(1-0.53)}{1002}}\) Calculate the margin of error: \(1.645 \times \sqrt{\frac{0.53(1-0.53)}{1002}} = 0.0310\) So, the confidence interval for the Pro-Choice position is: \(0.53 \pm 0.0310 = (0.499, 0.561)\) This means that we are 90% confident that the true proportion of adult Americans who favor the Pro-Choice position is between 49.9% and 56.1%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When conducting a survey or poll, researchers aim to understand the opinions or characteristics of a larger population by examining a segment of that population, called a sample. The sample proportion is a key statistic that represents the fraction of the sample with a certain characteristic or opinion.

In the context of the given exercise, researchers used a sample of 1002 adults to gauge the public's stance on abortion. They determined that 39% of the sample favored the 'right-to-life' position, meaning the sample proportion, denoted by \(\hat{p}\), is 0.39. Similarly, for the 'pro-choice' stance, the sample proportion is 53%, or \(\hat{p} = 0.53\). Understanding sample proportion is crucial, as it is the starting point for calculating the confidence interval, an estimate that aims to reflect the opinion of the overall population.
Critical Value
When creating a confidence interval, the critical value plays a crucial role. It determines the range within which the true population parameter is expected to lie with a specific level of confidence. The critical value is derived from the probability distribution of the statistic — often a z-distribution for large sample sizes when the population standard deviation is known or can be estimated.

For a given confidence level, say 90%, we want to find the z-value that corresponds to the middle 90% of the z-distribution. The remaining 10% is split between the two tails of the distribution (5% in each tail if looking for a two-tailed interval). In our exercise, this value is \(z_\frac{\alpha}{2} = 1.645\). This critical value helps ensure that if we were to repeat our sampling process numerous times, 90% of the confidence intervals we calculate would contain the true population proportion. Hence, understanding and finding the correct critical value is fundamental in constructing accurate confidence intervals.
Margin of Error
The margin of error is a statistic that indicates the likely size of the error in a sample estimate when compared to the actual value in the full population. It's an essential part of any confidence interval calculation, as it sets the bounds for the range of values within which the population parameter is expected to lie. In layman's terms, it tells us how much 'wiggle room' we should expect in our estimate due to the fact that we're using a sample and not surveying the entire population.

For example, in the exercise regarding the 'right-to-life' position, the margin of error was calculated to be \(1.645 \times \sqrt{\frac{0.39(1-0.39)}{1002}} = 0.0305\). This value is then used to determine the confidence interval, resulting in a range of 35.95% to 42.05%. It reflects our uncertainty inherent in the estimation process, and taking it into account helps us construct a realistic interval that acknowledges the limitations of our sample. The margin of error is influenced by factors such as sample size, variability in the data, and the desired confidence level.

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Most popular questions from this chapter

Born between 1980 and \(1990,\) Generation Next have lived in a post-Cold War world and a time of relative economic prosperity in America, but they have also experienced September 11 th and the fear of another attack, two Gulf Wars, the tragedy at Columbine High School, Hurricane Katrina, and the increasing polarization of public discourse. More than any who came before, Generation Next is engaged with technology, and the vast majority is dependent upon it. \({ }^{15}\) Suppose that a survey of 500 female and 500 male students in Generation Next, 345 of the females and 365 of the males reported that they decided to attend college in order to make more money. a. Construct a \(98 \%\) confidence interval for the difference in the proportions of female and male students who decided to attend college in order to make more money. b. What does it mean to say that you are "98\% confident"? c. Based on the confidence interval in part a, can you conclude that there is a difference in the proportions of female and male students who decided to attend college in order to make more money?

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