/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 The safety requirements for hard... [FREE SOLUTION] | 91Ó°ÊÓ

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The safety requirements for hard hats worn by construction workers and others, established by the American National Standards Institute (ANSI), specify that each of three hats pass the following test. A hat is mounted on an aluminum head form. An 8 -pound steel ball is dropped on the hat from a height of 5 feet, and the resulting force is measured at the bottom of the head form. The force exerted on the head form by each of the three hats must be less than 1000 pounds, and the average of the three must be less than 850 pounds. (The relationship between this test and actual human head damage is unknown.) Suppose the exerted force is normally distributed, and hence a sample mean of three force measurements is normally distributed. If a random sample of three hats is selected from a shipment with a mean equal to 900 and \(\sigma=100\), what is the probability that the sample mean will satisfy the ANSI standard?

Short Answer

Expert verified
Answer: The probability is approximately 19.3%.

Step by step solution

01

Identify the known values

The known values in this problem are: - Population mean (\(\mu\)) = 900 pounds - Population standard deviation (\(\sigma\)) = 100 pounds - Sample size (n) = 3 - ANSI standard for average force = 850 pounds
02

Calculate the standard deviation of the sample mean

The standard deviation of a sample mean (also known as the standard error) is given by the formula: $$ SE = \frac{\sigma}{\sqrt{n}} $$ Plugging in the known values, we get: $$ SE = \frac{100}{\sqrt{3}} \approx 57.74 $$
03

Calculate the z-score for the ANSI standard

A z-score is a measure of how many standard deviations a value is from the mean of its distribution. To calculate the z-score for the ANSI standard of 850 pounds, we use the formula: $$ z = \frac{(X - \mu)}{SE} $$ Plugging in the known values, we get: $$ z = \frac{(850 - 900)}{57.74} \approx -0.865 $$
04

Find the probability that the sample mean is less than 850 pounds

Now that we have the z-score, we can use a z-table or an online calculator to find the probability that the sample mean is less than 850 pounds. From a z-table or a calculator, we find that the probability associated with a z-score of -0.865 is approximately 0.193. Therefore, the probability that the sample mean will satisfy the ANSI standard is approximately 19.3%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
Understanding the normal distribution is fundamental in statistics. It is the bell-shaped curve that arises in numerous natural phenomena and indicates how values are distributed around the mean. A vital feature of the normal distribution is that it is symmetrical; most observations cluster around the central peak and the probabilities for values farther away from the mean taper off equally in both directions.

In the problem associated with construction hard hats, if the force exerted by the steel ball on the hats has a normal distribution, this implies that most of the time, the force measurements will be near the population mean (900 pounds in this case), with fewer instances of extremely low or high values.

When dealing with normally distributed data, we can employ various statistical tools like the z-score to make inferences about our sample in relation to the entire population.
Standard Deviation
The standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation means that the data points tend to be close to the mean, whereas a high standard deviation means that the data points are spread out over a wider range of values.

It's crucial to know the standard deviation of the whole population when addressing problems like the one provided. In this scenario, a standard deviation, symbolized by \(\sigma\), of 100 pounds indicates there is considerable variability in the forces exerted on the hard hats.

This measure helps us understand how uniform or varied the results from the hard hat test might be, and it is a critical component when calculating the standard error of the sample mean which is used to find the z-score.
Z-score
A z-score represents the number of standard deviations an observation is above or below the mean. In other words, it is a way of standardizing scores on the same scale to compare them directly. The z-score in our problem is calculated to see how far off the sample mean is from the population mean in terms of standard errors.

The z-score is calculated using the formula \( z = \frac{(X - \mu)}{SE} \) where \( X \) is the value we are comparing to the mean, \( \mu \) is the population mean, and \( SE \) is the standard error. Notice how the formula adjusts the raw score \( X \) by subtracting the population mean and then dividing by the standard error.

A negative z-score, such as -0.865 in the given problem, indicates that the sample mean is below the population mean. The further the z-score is from 0, whether positive or negative, the more unusual the observation is in comparison to the standard.
Sample Mean
The sample mean is simply the average of a sample. It's an estimate of the population mean, which, based on the central limit theorem, will have a normal distribution if the sample size is large enough, regardless of the shape of the population distribution.

In the context of our example, the sample mean is critical because ANSI's safety requirement is based on the average force exerted by the three hard hats being less than 850 pounds. When a large number of samples of size three are taken and the sample means calculated, these means will be distributed normally around the population mean (900 pounds with a standard deviation of 100 pounds).

Understanding the sample mean allows us to assess any given sample against the population parameters and safety standards, helping to maintain quality control in products such as safety equipment. The sample mean is then utilized in conjunction with other statistical measures, like the standard deviation and z-score, to determine the likelihood of a sample meeting specified criteria.

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Most popular questions from this chapter

News reports tell us that the average American is overweight. Many of us have tried to trim down to our weight when we finished high school or college. And, in fact, only \(19 \%\) of adults say they do not suffer from weight-loss woes. Suppose that the \(19 \%\) figure is correct, and that a random sample of \(n=100\) adults is selected. a. Does the distribution of \(\hat{p},\) the sample proportion of adults who do not suffer from excess weight, have an approximate normal distribution? If so, what is its mean and standard deviation? b. What is the probability that the sample proportion \(\hat{p}\) exceeds .25? c. What is the probability that \(\hat{p}\) lies within the interval .25 to \(.30 ?\) d. What might you conclude about \(p\) if the sample proportion exceeded .30?

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