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A random sample of \(n\) observations is selected from a population with standard deviation \(\sigma=1\). Calculate the standard error of the mean (SE) for these values of \(n\) a. \(n=1\) b. \(n=2\) c. \(n=4\) d. \(n=9\) e. \(n=16\) f. \(n=25\) g. \(n=100\)

Short Answer

Expert verified
Question: Calculate the standard error of the mean (SE) for each given value of n when the standard deviation (σ) is 1. a. n = 1 b. n = 2 c. n = 4 d. n = 9 e. n = 16 f. n = 25 g. n = 100 Answer: a. SE = 1 b. SE = 0.71 c. SE = 0.5 d. SE = 0.33 e. SE = 0.25 f. SE = 0.2 g. SE = 0.1

Step by step solution

01

a. n = 1

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{1}} = 1\)
02

b. n = 2

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{2}} = \frac{1}{1.41} = 0.71\)
03

c. n = 4

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{4}} = \frac{1}{2} = 0.5\)
04

d. n = 9

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{9}} = \frac{1}{3} = 0.33\)
05

e. n = 16

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{16}} = \frac{1}{4} = 0.25\)
06

f. n = 25

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{25}} = \frac{1}{5} = 0.2\)
07

g. n = 100

SE = \(\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt{100}} = \frac{1}{10} = 0.1\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Sample
A random sample is a subset taken from a larger population that is selected in such a way that each individual in the population has an equal chance of being chosen. This practice is crucial in statistics and data analysis because it ensures that the sample accurately reflects the diversity and characteristics of the full population.

When you take a random sample, you're aiming for a group that represents the entire population without bias or influence from external factors, like the researcher's preferences or environments. Thus, it forms the foundation for making predictions or inferences about the overall population. Here are some key points:
  • Random samples provide an unbiased representation of a population.
  • They help us make statistical inferences and ensure variability and diversity.
  • Random sampling reduces bias and aids in achieving generalizable results.
For instance, in calculating the standard error for different sample sizes in our problem, the concept of a random sample ensures that each value reflects the population characteristics consistently.
Population Standard Deviation
The population standard deviation (\(\sigma\)) measures the amount of variability or dispersion in a set of data points from a whole population. It gives us insights into how spread out the data points are around the mean of that population.

In simpler terms, a smaller standard deviation indicates that the data points tend to be closer to the mean, whereas a larger standard deviation implies that they are spread out more widely. Understanding the population standard deviation is essential, especially when calculating the standard error, because it influences how much the sample mean is expected to vary from the true population mean.
  • Helps assess the variability in a dataset.
  • Critical for calculating the standard error of the mean.
  • Fixed value for a given population, unlike sample standard deviation which can change with different samples.
For the given exercise, the population standard deviation was set to 1, simplifying the calculation of the standard error for different sample sizes.
Sample Size
Sample size, denoted as \(n\), is the number of observations or data points selected from a larger population to be included in a statistical sample. The size of your sample is vitally important as it directly affects the reliability and accuracy of the statistical estimates you make about the population.

Larger sample sizes tend to provide more accurate estimates because they reduce the effect of outliers and variations, thus enhancing the reliability of the results. Conversely, a smaller sample size may lead to less reliable results, since it might not capture the full extent of population variability.

When it comes to calculating the standard error of the mean, sample size plays a crucial role. The standard error is inversely related to the square root of the sample size:
  • Larger sample sizes reduce the standard error, leading to more accurate estimates.
  • Smaller sample sizes increase the standard error, possibly increasing the margin of error in estimates.
  • Influences how representative a sample is of the entire population.
In the provided example, different sample sizes were given to show how they affect the standard error, with larger sizes like 100 resulting in a smaller standard error compared to smaller sizes like 1.

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Most popular questions from this chapter

Some sports that involve a significant amount of running, jumping, or hopping put participants at risk for Achilles tendinopathy (AT), an inflammation and thickening of the Achilles tendon. A study in The American Journal of Sports Medicine looked at the diameter (in \(\mathrm{mm}\) ) of the affected and nonaffected tendons for patients who participated in these types of sports activities. \(^{9}\) Suppose that the Achilles tendon diameters in the general population have a mean of 5.97 millimeters (mm) with a standard deviation of \(1.95 \mathrm{~mm} .\) a. What is the probability that a randomly selected sample of 31 patients would produce an average diameter of \(6.5 \mathrm{~mm}\) or less for the nonaffected tendon? b. When the diameters of the affected tendon were measured for a sample of 31 patients, the average diameter was \(9.80 .\) If the average tendon diameter in the population of patients with AT is no different than the average diameter of the nonaffected tendons \((5.97 \mathrm{~mm})\), what is the probability of observing an average diameter of 9.80 or higher? c. What conclusions might you draw from the results of part b?

The safety requirements for hard hats worn by construction workers and others, established by the American National Standards Institute (ANSI), specify that each of three hats pass the following test. A hat is mounted on an aluminum head form. An 8 -pound steel ball is dropped on the hat from a height of 5 feet, and the resulting force is measured at the bottom of the head form. The force exerted on the head form by each of the three hats must be less than 1000 pounds, and the average of the three must be less than 850 pounds. (The relationship between this test and actual human head damage is unknown.) Suppose the exerted force is normally distributed, and hence a sample mean of three force measurements is normally distributed. If a random sample of three hats is selected from a shipment with a mean equal to 900 and \(\sigma=100\), what is the probability that the sample mean will satisfy the ANSI standard?

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Refer to Exercise \(7.75 .\) During a given week the number of defective bulbs in each of five samples of 100 were found to be \(2,4,9,7,\) and 11 . Is there reason to believe that the production process has been producing an excessive proportion of defectives at any time during the week?

Samples of \(n=100\) items were selected hourly over a 100 -hour period, and the sample proportion of defectives was calculated each hour. The mean of the 100 sample proportions was .035 a. Use the data to find the upper and lower control limits for a \(p\) chart. b. Construct a \(p\) chart for the process and explain how it can be used.

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