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Use Table 1 in Appendix I to find the following: a. \(P(x<12)\) for \(n=20, p=.5\) b. \(P(x \leq 6)\) for \(n=15, p=.4\) c. \(P(x>4)\) for \(n=10, p=.4\) d. \(P(x \geq 6)\) for \(n=15, p=.6\) e. \(P(3

Short Answer

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Question: Use the binomial table to find the probability for each scenario: Part a: Find the probability that \(x<12\) when \(n=20\) and \(p=0.5\). Part b: Find the probability that \(x \leq 6\) when \(n=15\) and \(p=0.4\). Part c: Find the probability that \(x>4\) when \(n=10\) and \(p=0.4\). Part d: Find the probability that \(x \geq 6\) when \(n=15\) and \(p=0.6\). Part e: Find the probability that \(3

Step by step solution

01

Part a: Finding \(P(x

First, we need to find the probability for \(x=0, 1, 2,\cdots, 11\). We can use Table 1 in Appendix I for this purpose. Look for the column with \(n=20\) and \(p=0.5\). Add up the probabilities for \(x=0\) to \(x=11\). The sum of these probabilities is the required probability \(P(x<12)\).
02

Part b: Finding \(P(x \leq 6)\) for \(n=15, p=.4\)

We want to find the probability for \(x=0, 1, 2,\cdots, 6\). Using Table 1 in Appendix I, look for the column with \(n=15\) and \(p=0.4\). Add up the probabilities for \(x=0\) to \(x=6\). The sum of these probabilities is the required probability \(P(x \leq 6)\).
03

Part c: Finding \(P(x>4)\) for \(n=10, p=.4\)

First, find the probability for \(x=0, 1, 2, 3, 4\). Look for the column with \(n=10\) and \(p=0.4\) in Table 1 in Appendix I. Add up the probabilities for \(x=0\) to \(x=4\). Subtract this sum from 1 to get the required probability \(P(x > 4)\). So, \(P(x>4) = 1 - P(x \leq 4)\).
04

Part d: Finding \(P(x \geq 6)\) for \(n=15, p=.6\)

First, find the probability for \(x=0, 1, 2,\cdots, 5\). Look for the column with \(n=15\) and \(p=0.6\) in Table 1 in Appendix I. Add up the probabilities for \(x=0\) to \(x=5\). Subtract this sum from 1 to get the required probability \(P(x \geq 6)\). So, \(P(x \geq 6) = 1 - P(x \leq 5)\).
05

Part e: Finding \(P(3

We want to find the probability for \(x=4, 5, 6\). Look for the column with \(n=10\) and \(p=0.5\) in Table 1 in Appendix I. Add up the probabilities for \(x=4\) to \(x=6\). The sum of these probabilities is the required probability \(P(3 < x < 7)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
A probability distribution gives us a map of all possible outcomes of a random variable and their corresponding probabilities. For a discrete random variable, like those found in binomial experiments, this distribution tells us how the probabilities are spread over each possible outcome. In the case of a binomial distribution, it models the number of successes in a fixed number of independent Bernoulli trials, each with the same probability of success.

For example, if you were to flip a coin (which represents a Bernoulli trial with two possible outcomes) 20 times, a binomial probability distribution would give you the probabilities of getting 0, 1, 2, ..., 20 heads. The distribution would be centered around the expected number of successes, which can be calculated using the formula: \[E(x) = n imes p\] where \(n\) is the number of trials and \(p\) is the probability of success on a single trial.

Understanding this allows us to ask questions about the likelihood of certain ranges of outcomes, such as in the given problem, where different parts of the distribution are summed to find specific probabilities.
Cumulative Probability
To determine cumulative probability, we sum the probabilities of all outcomes up to and including a particular event. It's like progressively counting every success up to a point, which is useful when we want to understand the likelihood of achieving up to a certain number of successes. In the exercise, you are asked to compute cumulative probabilities for conditions like \(P(x \leq 6)\) and \(P(x < 12)\).

When you add up these probabilities, you're essentially answering the question: "What is the probability that the random variable will take a value at or below a specific target?" This is an important concept because many real-world problems revolve around understanding the probability up to a certain point, rather than exactly at one point.

For instance, if we're calculating \(P(x \leq 6)\), we would sum the probabilities for cases from \(x=0\) to \(x=6\). Cumulative probability is especially helpful when considering worst-case scenarios or when assessing risk.
Appendix Tables
Appendix tables can be incredibly helpful in solving binomial probability questions. They provide pre-calculated probabilities for different combinations of \(n\) (number of trials), \(p\) (probability of success), and \(x\) (number of successes). These tables save significant time since you don't need to calculate each binomial probability from scratch.

How to use them? Simply find your desired \(n\) and \(p\) in the table, then look up the probabilities associated with the range of \(x\) values you're interested in. In the provided exercise, you refer to Appendix tables to quickly locate probabilities for specified \(n\), \(p\), and \(x\) ranges.

Key points to remember when using these tables are:
  • Ensure you're using the correct table that matches your binomial parameters.
  • Carefully locate the row and column that correspond to your \(n\), \(p\), and range of \(x\).
  • If you're calculating a range (like \(x<12\)), remember to sum the appropriate probabilities from the table.
This method makes the process of solving binomial probability problems both quicker and less prone to calculation errors.
Binomial Distribution
The binomial distribution is a discrete probability distribution that models the number of successes in a fixed number of independent experiments or trials, where each experiment has two possible outcomes, often termed as 'success' and 'failure'. Each trial in a binomial experiment is identical and independent, meaning the probability of success remains constant throughout.

One of the main points of understanding the binomial distribution is the binomial probability formula, which calculates the probability of exactly \(x\) successes in \(n\) trials: \[P(x) = \binom{n}{x} p^x (1-p)^{n-x}\] where \(\binom{n}{x}\) is the binomial coefficient, which can be read as "n choose x" and is calculated as \(\frac{n!}{x!(n-x)!}\), \(p\) is the probability of success, and \(1-p\) is the probability of failure on any given trial.

In the exercise, you're using the binomial distribution to determine the probabilities of various outcomes. For instance, with \(n = 20\) and \(p = 0.5\), you'd apply the formula to compute the probability for each necessary \(x\) and sum them to find cumulative probabilities. Understanding how to manipulate this distribution allows you to address a wide array of questions dealing with probability and statistics.

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Most popular questions from this chapter

Bacteria in Water Samples If a drop of water is placed on a slide and examined under a microscope, the number \(x\) of a particular type of bacteria present has been found to have a Poisson probability distribution. Suppose the maximum permissible count per water specimen for this type of bacteria is five. If the mean count for your water supply is two and you test a single specimen, is it likely that the count will exceed the maximum permissible count? Explain.

Parents who are concerned that their children are "accident prone" can be reassured, according to a study conducted by the Department of Pediatrics at the University of California, San Francisco. Children who are injured two or more times tend to sustain these injuries during a relatively limited time, usually 1 year or less. If the average number of injuries per year for school- age children is two, what are the probabilities of these events? a. A child will sustain two injuries during the year. b. A child will sustain two or more injuries during the year. c. A child will sustain at most one injury during the year.

Car Colors Car color preferences change over the years and according to the particular model that the customer selects. In a recent year, suppose that \(10 \%\) of all luxury cars sold were black. If 25 cars of that year and type are randomly selected, find the following probabilities: a. At least five cars are black. b. At most six cars are black. c. More than four cars are black. d. Exactly four cars are black. e. Between three and five cars (inclusive) are black. f. More than 20 cars are not black.

A psychiatrist believes that \(80 \%\) of all people who visit doctors have problems of a psychosomatic nature. She decides to select 25 patients at random to test her theory. a. Assuming that the psychiatrist's theory is true, what is the expected value of \(x\), the number of the 25 patients who have psychosomatic problems? b. What is the variance of \(x\), assuming that the theory is true? c. Find \(P(x \leq 14)\). (Use tables and assume that the theory is true.) d. Based on the probability in part \(\mathrm{c}\), if only 14 of the 25 sampled had psychosomatic problems, what conclusions would you make about the psychiatrist's theory? Explain.

Increased research and discussion have focused on the number of illnesses involving the organism Escherichia coli \((01257: \mathrm{H} 7),\) which causes a breakdown of red blood cells and intestinal hemorrhages in its victims. \({ }^{5}\) According to the Center for Disease Control, an estimated 73,000 cases of \(E\). coli infection and 61 deaths occur in the United States each year. A 2006 outbreak traced to wild pigs, who spread the bacteria into a spinach field in California, sickened 204 people in 26 states and 1 Canadian province. Outbreaks have occurred at a rate of 2.5 per \(100,000 .\) Let us suppose that this rate has not changed. a. What is the probability that at most five cases of E.coli per 100,000 are reported in California this year? b. What is the probability that more than five cases of E. coli are reported in California this year? c. Approximately \(95 \%\) of occurrences of \(E\). coli involve at most how many cases?

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