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A certain manufactured item is visually inspected by two different inspectors. When a defective item comes through the line, the probability that it gets by the first inspector is \(.1 .\) Of those that get past the first inspector, the second inspector will "miss" 5 out of \(10 .\) What fraction of the defective items get by both inspectors?

Short Answer

Expert verified
Answer: The overall probability that a defective item gets past both inspectors is 1/20 or 0.05.

Step by step solution

01

Identify the given probabilities

The probability that a defective item gets by the first inspector, P(First), is 0.1. The conditional probability that a defective item gets past the second inspector given it got past the first inspector, P(Second|First), is 5 out of 10, which can be written as 0.5.
02

Apply the conditional probability formula

We want to find the overall probability that a defective item gets past both inspectors. Using the conditional probability formula, this can be represented as: P(Both) = P(First) * P(Second|First)
03

Calculate the overall probability

Substitute the given probabilities into the formula: P(Both) = 0.1 * 0.5
04

Simplify the expression

Multiply the probabilities: P(Both) = 0.05
05

Express the probability as a fraction

The overall probability that a defective item gets past both inspectors is 0.05 or 5 out of 100, which can be simplified as: P(Both) = \frac{1}{20} So, 1 out of every 20 defective items gets past both inspectors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics that helps us understand the likelihood of different outcomes. It's like having a crystal ball but supported by numbers and formulas.

When dealing with situations where randomness is involved, probability theory helps predict how probable an outcome is. We express probability values between 0 and 1. A probability of 0 means the event will never happen, and a probability of 1 means it will definitely happen.

For example, in our exercise, we calculate probabilities for inspecting items. The scenario involves a chain of events, where different inspectors evaluate items, and we're interested in how many defective items can slip through without being noticed. This is where the concept of conditional probability comes into play.

Conditional probability is when the probability of one event depends on another event occurring. In our problem, once an item has passed the first inspector, it enters a new stage; the probability is then calculated based on this new condition.
Inspector Problem
The Inspector Problem is an interesting scenario in probability theory where items (such as manufactured goods) are evaluated by inspectors for defects. Each inspector has the chance to either catch or miss a defective item. Understanding the flow and interaction of probabilities at each step is key.

In our exercise, two separate events happen. First, a defective item must pass the first inspector. We know the probability here is 0.1, meaning there's a 10% chance a defective item is not spotted by the first inspector.

Next comes the conditional probability, noted as 0.5, or 50%, indicating the chance the item goes unnoticed by the second inspector, given that the first inspector missed it.

To find the total probability of a defective item escaping both inspectors, we multiply these probabilities. This multiplication aligns with the idea that each step is independent, yet collectively determines the final outcome. With this approach, problems such as ensuring items are up to standard can be analyzed with precision.
Defective Items Inspection
Detecting defective items involves processes and inspections to ensure products meet quality standards. This task becomes crucial in manufacturing lines where lots of items are produced and only a few may have defects.

The exercise we tackled highlights the significance of multiple inspection stages. Such layers in quality checks increase the likelihood of catching defective items.
  • First Step: The defective item gets past the initial inspector. This happens with a probability of 0.1 as stated.

  • Second Step: Only items that pass the first check are considered, and then go through a second evaluation. This next layer has a conditional pass rate of 0.5.

Ultimately, the combined procedure illustrates a real-world application of probability. The goal is to minimize defective products reaching the customers, ensuring higher satisfaction. Thus, understanding the numbers behind each inspection phase is vital for improving these inspections.

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