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Maybe too good. according to tests performed by the consumer testing division of Good Housekeeping. Nutritional information provided by Kentucky Fried Chicken claims that each small bag of Potato Wedges contains 4.8 ounces of food, for a total of 280 calories. A sample of 10 orders from KFC restaurants in New York and New Jersey averaged 358 calories. \({ }^{16}\) If the standard deviation of this sample was \(s=54,\) is there sufficient evidence to indicate that the average number of calories in small bags of KFC Potato Wedges is greater than advertised? Test at the \(1 \%\) level of significance.

Short Answer

Expert verified
Answer: Yes, there is sufficient evidence to indicate that the average number of calories in small bags of KFC Potato Wedges is greater than advertised.

Step by step solution

01

Test formulation

We will perform a one-sample t-test, where the null hypothesis \(H_0\) states that the average number of calories in small bags of KFC Potato Wedges is equal to the advertised value, and the alternative hypothesis \(H_a\) states that the average number of calories in small bags of KFC Potato Wedges is greater than advertised. \(H_0: \mu = 280\) \(H_a: \mu > 280\)
02

Calculate the test statistic

The test statistic for a one-sample t-test is given by: \(t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}}\) Where \(\bar{x}\) is the sample mean, \(\mu_0\) is the hypothesized population mean, s is the sample standard deviation, and n is the sample size. In this case: \(\bar{x} = 358\) \(\mu_0 = 280\) \(s = 54\) \(n = 10\) Plug these values into the formula: \(t = \frac{358 - 280}{\frac{54}{\sqrt{10}}}\)
03

Compute the test statistic value

Calculate the value of t: \(t = \frac{78}{17.086} \approx 4.57\)
04

Calculate the critical value

The problem states that we are working with a significance level of 1% (\(\alpha = 0.01\)) and the alternative hypothesis is one-tailed (\(H_a: \mu > 280\)). Calculate the critical t-value using a t-distribution table or a calculator with 9 degrees of freedom (10 - 1 = 9) and a 1% significance level: \(t_{critical} \approx 2.821\)
05

Compare the test statistic with the critical value

We compare the calculated t-value (4.57) with the critical t-value (2.821). Since the calculated t-value is greater than the critical value, we reject the null hypothesis: \(4.57 > 2.821\)
06

Conclusion

We found enough evidence to reject the null hypothesis at the 1% level of significance, which means we can conclude that there is sufficient evidence to indicate that the average number of calories in small bags of KFC Potato Wedges is greater than advertised.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In statistical testing, the null hypothesis is a fundamental concept that acts as the starting point for any test. Its main purpose is to propose a default assumption about a particular parameter of a population. In our KFC potato wedges example, the null hypothesis, denoted as \(H_0\), states that the average number of calories in small bags of KFC potato wedges is exactly equal to the advertised value, which is 280 calories. Simply put, it is the claim that there is no difference between the observed sample data and the stated average.The null hypothesis works on the presumption of no effect or no difference, aiming to disprove itself through statistical evidence. It is assumed true until sufficient evidence suggests otherwise. This implies that under the null hypothesis:
  • The sample mean is expected to be close to the population mean.
  • Any deviation from the population mean can be attributed to random sampling variation.
Understanding the null hypothesis is crucial, as it forms the basis of the decision-making process in statistical tests.
Alternative Hypothesis
The alternative hypothesis is an integral part of hypothesis testing. It represents a contrary position to the null hypothesis and expresses what researchers aim to support through their analysis. In the scenario with KFC's potato wedges, the alternative hypothesis, denoted as \(H_a\), posits that the average number of calories in small bags of KFC potato wedges is greater than the advertised 280 calories.This hypothesis signals a difference or effect that researchers want to detect. In hypothesis testing, the goal becomes either to provide support for the alternative hypothesis by showing that the null hypothesis can likely be rejected, or to show that the evidence is insufficient to reject the null hypothesis.Key points about the alternative hypothesis:
  • It is considered true when the null hypothesis is rejected based on statistical evidence.
  • In our case, it emphasizes the suspicion that KFC potato wedges contain more calories than advertised, requiring evidence to support this claim.
  • It is always directional (greater than, less than) or non-directional (not equal to), specifying the nature of the expected difference.
Significance Level
The significance level is a critical aspect of hypothesis testing used to determine whether to reject the null hypothesis. Denoted by \(\alpha\), it specifies the probability of committing a Type I error, which is the error made by rejecting a true null hypothesis. In simple terms, it reflects the researchers' tolerance for false positives.In our example, the test is conducted at a 1% significance level, which means:
  • There's a 1% risk of concluding that the average calories are more than advertised when, in fact, they are not.
  • A smaller \(\alpha\) indicates stricter evidence is required to reject the null hypothesis.
  • This choice controls how stringent the test is, balancing the need for evidence against the acceptance of possible errors.
Choosing a significance level depends on the context of the test. In some fields, a 5% level is standard, but health and safety applications often demand a more stringent 1% level, as seen in our exercise.
Critical Value
The critical value is a key element in determining the outcome of hypothesis tests. It represents the threshold beyond which the null hypothesis is rejected. It is derived from the test's specific distribution and is influenced by the chosen significance level and degrees of freedom.In the KFC potato wedges problem, with a significance level of 1% and 9 degrees of freedom (since there are 10 samples), we find the critical value using a t-distribution table. The critical t-value for a one-sample t-test in this context is approximately 2.821.Understanding critical values involves:
  • Comparing the calculated test statistic's value to this threshold.
  • Rejecting \(H_0\) if the test statistic surpasses this value, indicating enough evidence against \(H_0\).
  • Thus, in our example, since the test statistic (4.57) is greater than the critical value (2.821), the null hypothesis is rejected.
The critical value provides a concrete benchmark that assists in making decisions based on statistical evidence.

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Most popular questions from this chapter

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