/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 An experiment was conducted to c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An experiment was conducted to compare the densities (in ounces per cubic inch) of cakes prepared from two different cake mixes. Six cake pans were filled with batter \(\mathrm{A},\) and six were filled with batter B. Expecting a variation in oven temperature, the experimenter placed a pan filled with batter A and another with batter B side by side at six different locations in the oven. The six paired observations of densities are as follows: \begin{tabular}{l|llllll} Batter A & .135 & .102 & .098 & .141 & .131 & .144 \\\ \hline Batter B & .129 & .120 & .112 & .152 & .135 & .163 \end{tabular} a. Do the data present sufficient evidence to indicate a difference between the average densities of cakes prepared using the two types of batter? b. Construct a \(95 \%\) confidence interval for the difference between the average densities for the two mixes

Short Answer

Expert verified
To answer this question, follow the steps and provide the t-value, t-critical, and the confidence interval as part of your answer.

Step by step solution

01

Calculate the differences between paired observations

Compute the difference between each paired observation (Batter A - Batter B). Write the differences in a new row.
02

Calculate the mean and standard deviation of the differences

Calculate the mean and standard deviation of the differences. The mean is the sum of the differences divided by the number of differences (n = 6). The standard deviation can be calculated as: \(\sqrt{\frac{\sum(d - \overline{d})^2}{n-1}}\)
03

Perform paired t-test

Perform a paired t-test with the null hypothesis stating no difference between the average densities of cakes prepared using the two types of batter, and the alternative hypothesis indicating a difference exists. Calculate the t-value as: \(t = \frac{\overline{d}}{\frac{S_d}{\sqrt{n}}}\)
04

Calculate t-critical and determine if there is a significant difference

With a 95% confidence level and 6 - 1 degrees of freedom, we calculate the t-critical. Compare the absolute value of the calculated t-value with the t-critical. If the absolute t-value is greater than the t-critical, we reject the null hypothesis and conclude that there is a significant difference between the average densities of cakes prepared using Batter A and Batter B.
05

Calculate the 95% confidence interval

Construct a 95% confidence interval for the difference between the average densities using the following formula: \((\overline{d} - t_{critical} \cdot \frac{S_d}{\sqrt{n}}, \overline{d} + t_{critical} \cdot \frac{S_d}{\sqrt{n}})\) This interval will give us the range in which we are 95% confident that the true difference between the average densities of cakes prepared using Batter A and Batter B lies.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Hypothesis Testing
Statistical hypothesis testing plays a critical role in scientific research and data analysis. It provides a structured framework for evaluating whether the observed data is significantly different from the presumed state or just a result of random variations. In the paired t-test scenario from the exercise, we apply hypothesis testing to determine if there is a true difference in cake densities between two different batters.

The null hypothesis (\( H_0 \)) asserts that there is no difference between the groups – in this case, that Batter A and Batter B produce cakes of identical average densities. In contrast, the alternative hypothesis (\( H_a \text{ or } H_1 \)) suggests that there is a difference. When performing the test, if we find enough evidence to refute the null hypothesis within a chosen level of confidence – commonly 95% – we consider the result statistically significant. This means that we can accept the alternative hypothesis with a certain degree of certainty that the observed variation is not due to random chance alone.
Confidence Interval
A confidence interval is a range of values that is likely to contain the true value of an unknown population parameter. It is used to estimate the precision of a sample statistic. In the context of paired t-tests, a 95% confidence interval provides a range for the mean difference between paired observations that we are 95% confident includes the true mean difference.

The construction of this interval is based on the mean of the differences, the standard deviation of these differences, and the t-distribution. The broader the interval, the less precise is our estimate, which is why researchers might desire narrower intervals to increase precision. However, a higher level of confidence would typically yield a wider interval due to increased uncertainty associated with that confidence level.
Standard Deviation
The concept of standard deviation is pivotal in understanding the variability of data. It measures the spread of observations from their mean, thus indicating how much the individual observations differ from the average value. In the exercise's paired t-test, the standard deviation of the density differences \( S_d \)

provides insight into how much variation exists within the paired observations. A high standard deviation implies that the differences between each pair are broadly scattered, whereas a low standard deviation suggests the differences are closely clustered around the mean difference. Computing this statistic allows for a more comprehensive understanding of the consistency of the differences observed between Batter A and Batter B.
Mean Difference
Mean difference is a critical measure used to illustrate the average discrepancy between paired observations. In many scientific tests, including the one in the exercise, the mean difference \( \overline{d} \) tells us how much one set, Batter A in our case, deviates from another, Batter B, on average.

This measure acts as the centerpiece of the paired t-test, as it is directly used in the calculation of the t-value and ultimately helps determine the presence of a significant difference between the two sets of data. Any observed mean difference would suggest a systematic variation that could be attributed to the difference in cake mixes. However, it's important to differentiate between statistical significance and practical significance when interpreting the mean difference.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following data are the response times in seconds for \(n=25\) first graders to arrange three objects by size. \(\begin{array}{lllll}5.2 & 3.8 & 5.7 & 3.9 & 3.7\end{array}\) \(\begin{array}{lllll}4.2 & 4.1 & 4.3 & 4.7 & 43\end{array}\) \(\begin{array}{lllll}3.1 & 2.5 & 3.0 & 4.4 & 48\end{array}\) \(\begin{array}{lllll}3.6 & 3.9 & 4.8 & 53 & 42\end{array}\) \(\begin{array}{lll}47 & 33 & 42\end{array}\) 54 Find a \(95 \%\) confidence interval for the average response time for first graders to arrange three objects by size. Interpret this interval.

An experiment published in The American Biology Teacher studied the efficacy of using \(95 \%\) ethanol or \(20 \%\) bleach as a disinfectant in removing bacterial and fungal contamination when culturing plant tissues. The experiment was repeated 15 times with each disinfectant, using eggplant as the plant tissue being cultured. \({ }^{8}\) Five cuttings per plant were placed on a petridish for each disinfectant and stored at \(25^{\circ} \mathrm{C}\) for 4 weeks. The observation reported was the number of uncontaminated eggplant cuttings after the 4 -week storage. Disinfectant \(95 \%\) Ethanol \(20 \%\) Bleach \begin{tabular}{lcc} \hline Mean & 3.73 & 4.80 \\ Variance & 2.78095 & .17143 \\ \(n\) & 15 & 15 \\ & Pooled variance 1.47619 & \end{tabular} a. Are you willing to assume that the underlying variances are equal? b. Using the information from part a, are you willing to conclude that there is a significant difference in the mean numbers of uncontaminated eggplants for the two disinfectants tested?

A paired-difference experiment was conducted using \(n=10\) pairs of observations. a. Test the null hypothesis \(H_{0}:\left(\mu_{1}-\mu_{2}\right)=0\) against \(H_{\mathrm{a}}:\left(\mu_{1}-\mu_{2}\right) \neq 0\) for \(\alpha=.05, d=.3,\) and \(s_{d}^{2}=.16 .\) Give the approximate \(p\) -value for the test. b. Find a \(95 \%\) confidence interval for \(\left(\mu_{1}-\mu_{2}\right)\).c. How many pairs of observations do you need if you want to estimate \(\left(\mu_{1}-\mu_{2}\right)\) correct to within .1 with probability equal to \(.95 ?\)

An experiment was conducted to compare the mean lengths of time required for the bodily absorption of two drugs \(\mathrm{A}\) and \(\mathrm{B}\). Ten people were randomly selected and assigned to receive one of the drugs. The length of time (in minutes) for the drug to reach a specified level in the blood was recorded, and the data summary is given in the table: Drug A Drug B \(\bar{x}_{1}=27.2 \quad \bar{x}_{2}=33.5\) \(s_{1}^{2}=16.36 \quad s_{2}^{2}=18.92\) a. Do the data provide sufficient evidence to indicate a difference in mean times to absorption for the two drugs? Test using \(\alpha=.05 .\) b. Find the approximate \(p\) -value for the test. Does this value confirm your conclusions? c. Find a \(95 \%\) confidence interval for the difference in mean times to absorption. Does the interval confirm your conclusions in part a?

An article in Archaeometry involved an analysis of 26 samples of Romano- British pottery, found at four different kiln sites in the United Kingdom. \(^{9}\) The samples were analyzed to determine their chemical composition and the percentage of aluminum oxide in each of \(10 \mathrm{sam}-\) ples at two sites is shown below. \begin{tabular}{c|c} Island Thorns & Ashley Rails \\\ \hline 18.3 & 17.7 \\ 15.8 & 18.3 \\ 18.0 & 16.7 \\ 18.0 & 14.8 \\ 20.8 & 19.1 \end{tabular} Does the data provide sufficient information to indicate that there is a difference in the average percentage of aluminum oxide at the two sites? Test at the \(5 \%\) level of significance.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.