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A fair coin is tossed three times. Let \(X\) be the number of heads that turn up on the first two tosses and \(Y\) the number of heads that turn up on the third toss. Give the distribution of (a) the random variables \(X\) and \(Y\). (b) the random variable \(Z=X+Y\). (c) the random variable \(W=X-Y\).

Short Answer

Expert verified
(a) \(X\sim \text{Binomial}(2, 0.5)\), \(Y\sim \text{Bernoulli}(0.5)\). (b) \(Z\sim \text{Binomial}(3, 0.5)\). (c) Distribution: \(P(W=-1)=\frac{1}{8}\), \(P(W=0)=\frac{1}{2}\), \(P(W=1)=\frac{3}{8}\).

Step by step solution

01

Understanding the Coin Toss

We have a fair coin tossed three times. Define two random variables: 1. \(X\): how many heads are obtained in the first two tosses, and 2. \(Y\): how many heads are obtained on the third toss.
02

Distribution of Random Variable X

For the first two tosses, each has a 50% chance of being heads, so \(X\) can take values 0, 1, or 2. The probabilities are: all tails, \(P(X=0) = \frac{1}{4}\); one head, \(P(X=1) = \frac{2}{4}\); both heads, \(P(X=2) = \frac{1}{4}\). Thus, the distribution of \(X\) is a binomial distribution \(X \sim \text{Binomial}(2, 0.5)\).
03

Distribution of Random Variable Y

For the third toss, the random variable \(Y\) can be either 0 (tail) or 1 (head). Since it is a single toss of a fair coin, \(P(Y=0) = \frac{1}{2}\) and \(P(Y=1) = \frac{1}{2}\). Thus, \(Y\) is a Bernoulli distribution with parameter 0.5.
04

Distribution of Random Variable Z

Since \(Z = X + Y\), the distribution of \(Z\) is the convolution of a binomial distribution \(\text{Binomial}(2, 0.5)\) and a Bernoulli distribution. \(Z\) can take values from 0 to 3 with probabilities: \(P(Z=0)=\frac{1}{8}\), \(P(Z=1)=\frac{3}{8}\), \(P(Z=2)=\frac{3}{8}\), \(P(Z=3)=\frac{1}{8}\). Thus, \(Z\) is \(\text{Binomial}(3, 0.5)\).
05

Distribution of Random Variable W

Since \(W = X - Y\), the possible values are -1 (when \(X=0\), \(Y=1\)), 0 (when \(X=1\), \(Y=1\) or \(X=0\), \(Y=0\) or \(X=2\), \(Y=2\)), 1 (when \(X=2\), \(Y=1\) or \(X=1\), \(Y=0\)). Probabilities are \(P(W=-1) = \frac{1}{8}\), \(P(W=0) = \frac{4}{8}\), \(P(W=1) = \frac{3}{8}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a common way to model the number of successes in a fixed number of independent experiments. Each experiment has two possible outcomes: success or failure.
In the context of a coin toss, a 'success' might mean getting a head. This is what we see with the random variable \(X\) in our coin toss exercise, which represents the number of heads attained in the first two tosses out of three.

Here's how it works:
  • The number of experiments is fixed, which in our case is two tosses.
  • Each coin toss is independent, meaning the result of one doesn't affect the other.
  • The probability of getting a head (success) on each toss is 0.5, making the coin fair.
The binomial distribution is described with parameters (n, p), where \(n\) is the number of trials, and \(p\) is the probability of success. For \(X\), \(X \sim \text{Binomial}(2, 0.5)\).
The possible outcomes for \(X\) (0, 1, or 2 heads) have probabilities calculated as follows:
  • 0 heads: \(P(X=0)=\frac{1}{4}\)
  • 1 head: \(P(X=1)=\frac{2}{4}\)
  • 2 heads: \(P(X=2)=\frac{1}{4}\)
Bernoulli Distribution
A Bernoulli distribution models a single experiment with two possible outcomes: success (1) or failure (0).
This distribution is named after Jacob Bernoulli. It's incredibly simple yet forms the building block for more complex probability models. In our coin toss exercise, the random variable \(Y\) represents the outcome of the third toss.

Key aspects of the Bernoulli distribution include:
  • It's based on a single trial or experiment.
  • The probability of success (e.g., getting a head) is represented by \(p\), and with a fair coin, it's 0.5.
  • The outcome is either a head (success) or a tail (failure).
So for \(Y\), the Bernoulli distribution is noted as \(Y \sim \text{Bernoulli}(0.5)\). The probabilities here are straightforward:
  • Head (success, \(Y=1\)): \(P(Y=1)=\frac{1}{2}\)
  • Tail (failure, \(Y=0\)): \(P(Y=0)=\frac{1}{2}\)
Random Variables
Random variables are essential in probability. They are used to map outcomes of a probability experiment to numerical values.
In our exercise, random variables like \(X\) and \(Y\) represent specific aspects of the coin toss outcomes.

Characteristics of random variables include:
  • They allow for quantitative analysis of random phenomena.
  • In our coin problem, they assign numbers (0, 1, etc.) to specific events (e.g., how many heads appear).
  • They can be discrete, taking specific values, or continuous, with an infinite number of possible values.
For instance:
  • \(X\) counts the heads in the first two tosses, making it a discrete variable with three possible values: 0, 1, or 2.
  • \(Y\) considers the third toss and also is discrete but simpler, with just two possible results: 0 or 1.
Understanding random variables helps us structure and solve probability problems by converting real-world randomness into structured mathematical frameworks.

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