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Let \(\mathbf{P}\) be the transition matrix of an \(r\) -state ergodic chain. Prove that, if the diagonal entries \(p_{i i}\) are positive, then the chain is regular.

Short Answer

Expert verified
The positive diagonal entries ensure the chain is aperiodic, making it regular when coupled with ergodicity.

Step by step solution

01

Understanding Ergodic Chains

An ergodic chain is a type of Markov chain where every state can be reached from every other state in a finite number of steps, implying the chain is both irreducible and aperiodic. We need to demonstrate regularity, meaning that some power of the transition matrix has strictly positive entries.
02

Analyze the Definition of Regular Chains

A Markov chain is regular if its transition matrix \(P\) raised to some power results in a matrix where all entries are positive. This means every state can reach every other state with a positive probability after a certain number of steps, regardless of the initial state.
03

Study the Effect of Positive Diagonal Entries

If each diagonal entry \(p_{ii}\) in the matrix \(P\) is positive, this implies that there is a positive probability of a Markov chain staying in the same state for one step. This is a key aspect in breaking potential periodicity.
04

Use Positive Diagonal Entries to Demonstrate Regularity

These positive diagonal entries ensure aperiodicity because every state can stay as it is in one time step with some probability. Hence, given that the chain is already irreducible (as it’s ergodic), the presence of positive diagonal entries ensures that some power will lead to a positive entry matrix.
05

Conclude the Proof by Showing Regularity

By raising the matrix \(P\) to a sufficiently high power, we can ensure all entries become positive due to irreducibility and the positive diagonal entries eliminate periodicity, confirming that the chain is regular.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Ergodic Chains
Ergodic chains are a fascinating concept in the study of Markov chains. The term "ergodic" relates to the ability of a Markov process to sample evenly over the states, which implies that every state can be reached from any other state. This property is crucial because it ensures that the process doesn't get stuck in any subset of states. In simpler terms, an ergodic chain is both irreducible and aperiodic.

To break it down:
  • Irreducibility means that for any state in the chain, there is a path to every other state. No subset of states can isolate themselves from the rest of the chain.
  • Aperiodicity ensures that the chain doesn't oscillate between states in a predictable cycle. It's a way of saying the system doesn't have cycles of fixed length that traps the sequence.
Hence, if a Markov chain is ergodic, you can have confidence that you can explore the entire state space no matter where you begin.
The Role of Transition Matrix
The transition matrix is a cornerstone of understanding how states transition in a Markov chain. Simply put, it is a square matrix where each element represents the probability of moving from one state to another.

Here's why it is important:
  • The size of the matrix is determined by the number of states (\( n \) in a chain.
  • Each row in the matrix sums up to 1, since it represents the probability distribution over future states.
  • Diagonal elements indicate the likelihood of staying in the same state.
It is through the transition matrix that we can analyze the long-term behavior of a Markov chain. By raising the matrix to a power, the future states after multiple steps can be determined, which helps assess whether a chain is regular or not. Understanding the entries and how they relate to the physical process modeled is key to grasping Markov dynamics.
Identifying a Regular Markov Chain
A regular Markov chain reflects a property where the transition matrix, when raised to a certain power, results in all entries being positive. This characteristic is significant because it guarantees that, eventually, every state can be reached from any other state with positive probability.

To recognize a regular Markov chain, one must check if a power of the transition matrix yields only positive entries. This normally involves examining:
  • General connectivity between states.
  • Avoidance of absorbing states, where the process potentially could end or "stick".
The presence of strictly positive elements confirms that no state is strictly isolated and the process is free of additional layers or cycles.
Implications of Positive Diagonal Entries
Positive diagonal entries in a transition matrix play a vital role in confirming the regularity of a Markov chain. Such entries suggest that there's a positive probability of the process remaining in the same state during the next transition step.

This self-loopy feature helps break periodicity in chains, which is crucial because without periodicity, the process can move fluidly between states rather than being trapped in cycles.
  • It suggests flexibility and freedom of movement in the Markov chain.
  • Supports further interactions between states that enhance irreducibility.
Thus, having positive diagonal entries is an influential factor in ensuring that over time, the chain displays regular characteristics. It reinforces the mixing property of ergodic chains, where every state effectively communicates with every other state.

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Most popular questions from this chapter

Show that if \(\mathbf{P}\) is the transition matrix of a regular Markov chain, and \(\mathbf{W}\) is the matrix each of whose rows is the fixed probability vector corresponding to \(\mathbf{P},\) then \(\mathbf{P} \mathbf{W}=\mathbf{W},\) and \(\mathbf{W}^{k}=\mathbf{W}\) for all positive integers \(k\).

Find the matrices \(\mathbf{P}^{2}, \mathbf{P}^{3}, \mathbf{P}^{4},\) and \(\mathbf{P}^{n}\) for the Markov chain determined by the transition matrix \(\mathbf{P}=\left(\begin{array}{cc}1 & 0 \\ 0 & 1\end{array}\right) .\) Do the same for the transition matrix \(\mathbf{P}=\left(\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right) .\) Interpret what happens in each of these processes.

In the Leontief economic model, \(^{8}\) there are \(n\) industries \(1,2, \ldots, n\). The ith industry requires an amount \(0 \leq q_{i j} \leq 1\) of goods (in dollar value) from company \(j\) to produce 1 dollar's worth of goods. The outside demand on the industries, in dollar value, is given by the vector \(\mathbf{d}=\left(d_{1}, d_{2}, \ldots, d_{n}\right) .\) Let \(\mathbf{Q}\) be the matrix with entries \(q_{i j}\). (a) Show that if the industries produce total amounts given by the vector \(\mathbf{x}=\left(x_{1}, x_{2}, \ldots, x_{n}\right)\) then the amounts of goods of each type that the industries will need just to meet their internal demands is given by the vector \(\mathbf{x} \mathbf{Q}\) (b) Show that in order to meet the outside demand \(\mathbf{d}\) and the internal demands the industries must produce total amounts given by a vector \(\mathbf{x}=\left(x_{1}, x_{2}, \ldots, x_{n}\right)\) which satisfies the equation \(\mathbf{x}=\mathbf{x} \mathbf{Q}+\mathbf{d}\) (c) Show that if \(\mathbf{Q}\) is the \(\mathbf{Q}\) -matrix for an absorbing Markov chain, then it is possible to meet any outside demand \(\mathbf{d}\). (d) Assume that the row sums of \(\mathbf{Q}\) are less than or equal to 1 . Give an economic interpretation of this condition. Form a Markov chain by taking the states to be the industries and the transition probabilites to be the \(q_{i j}\). Add one absorbing state 0 . Define $$ q_{i 0}=1-\sum_{j} q_{i j} $$ Show that this chain will be absorbing if every company is either making a profit or ultimately depends upon a profit-making company. (e) Define \(\mathbf{x} \mathbf{c}\) to be the gross national product. Find an expression for the gross national product in terms of the demand vector \(\mathbf{d}\) and the vector t giving the expected time to absorption.

Let \(\mathbf{P}\) be the transition matrix of an ergodic Markov chain and \(\mathbf{P}^{*}\) the reverse transition matrix. Show that they have the same fixed probability vector w.

Here is a trick to try on your friends. Shuffle a deck of cards and deal them out one at a time. Count the face cards each as ten. Ask your friend to look at one of the first ten cards; if this card is a six, she is to look at the card that turns up six cards later; if this card is a three, she is to look at the card that turns up three cards later, and so forth. Eventually she will reach a point where she is to look at a card that turns up \(x\) cards later but there are not \(x\) cards left. You then tell her the last card that she looked at even though you did not know her starting point. You tell her you do this by watching her, and she cannot disguise the times that she looks at the cards. In fact you just do the same procedure and, even though you do not start at the same point as she does, you will most likely end at the same point. Why?

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