/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Let \(\mathbf{P}\) be the transi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(\mathbf{P}\) be the transition matrix of an ergodic Markov chain and \(\mathbf{P}^{*}\) the reverse transition matrix. Show that they have the same fixed probability vector w.

Short Answer

Expert verified
The matrices \(\mathbf{P}\) and \(\mathbf{P}^{*}\) share the same fixed probability vector \(\mathbf{w}\) due to the detailed balance conditions.

Step by step solution

01

Understanding the Problem

We have two matrices, the transition matrix \(\mathbf{P}\) of an ergodic Markov chain and its reverse transition matrix \(\mathbf{P}^{*}\). We need to show that both matrices share the same fixed probability vector \(\mathbf{w}\).
02

Define Fixed Probability Vector

A fixed probability vector \(\mathbf{w}\) for a Markov chain's transition matrix \(\mathbf{P}\) satisfies the equation \(\mathbf{w} \mathbf{P} = \mathbf{w}\). For \(\mathbf{w}\) to be a valid probability vector, its entries should be non-negative and sum to 1.
03

Reverse Transition Matrix Explanation

The reverse transition matrix \(\mathbf{P}^{*}\) is derived from \(\mathbf{P}\) such that if \(p_{ij}\) are the original transition probabilities, then \(p^*_{ij} = \frac{w_j p_{ji}}{w_i}\), where \(\mathbf{w}\) is the fixed probability vector of \(\mathbf{P}\). This ensures that the detailed balance equations are satisfied.
04

Show Fixed Vector for \(\mathbf{P}^{*}\)

Given the equation \(\mathbf{w} \mathbf{P} = \mathbf{w}\), substitute in the reverse matrix to show that \(\mathbf{w} \mathbf{P}^{*} = \mathbf{w}\). Using the detailed balance equations \(w_i p_{ij} = w_j p_{ji}\), prove that \(\sum w_i p^*_{ij} = w_j\), establishing \(\mathbf{w}\) as the fixed vector for \(\mathbf{P}^{*}\) too.
05

Validate Solution with Detailed Balance

By verifying that both \(\mathbf{P}\) and \(\mathbf{P}^{*}\) retain the properties of a Markov chain with the detailed balance condition fulfilled, we confirm that \(\mathbf{w}\) indeed serves as the identical fixed probability vector for both matrices.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ergodic Markov Chain
When we talk about an ergodic Markov chain, we refer to a special type of Markov chain with some fascinating properties. The chain is said to be ergodic if it is possible to go from any state to any other state in some number of steps. This means that the Markov chain is irreducible, and it can explore the entire state space. It brings a sense of connectivity to the states.
Moreover, an ergodic Markov chain is also aperiodic, meaning that the time steps for returning to a state are not fixed multiples of a number greater than 1. Together, these properties ensure that the chain has a long-term behavior that reaches a steady state.
  • A Markov chain is irreducible if it can move from any state to any other state.
  • It is aperiodic if return times to a state are not fixed intervals.
This steady-state behavior is what allows us to identify a fixed probability vector, a key concept in understanding what happens as we let the Markov chain run in the long term.
Transition Matrix
The transition matrix, denoted as \(\mathbf{P}\), is a central concept in Markov chains. Imagine this matrix as a roadmap that guides how the chain moves from one state to another. Each entry \(p_{ij}\) in the matrix represents the probability of transitioning from state \(i\) to state \(j\). These probabilities are non-negative and each row sums up to 1, symbolizing a total probability of staying within some state.
The transition matrix of an ergodic Markov chain has some unique characteristics. Because of the irreducible nature of the chain, all row vectors in \(\mathbf{P}\) are eventually able to influence any state, ensuring that every state communicates with every other state.
  • Each row in \(\mathbf{P}\) sums up to 1: \(\sum_j p_{ij} = 1\).
  • \(p_{ij}\) reflects the chance of moving from state \(i\) to state \(j\).
Maintaining this structure helps in finding solutions like the fixed probability vector that remains the same under the chain's dynamics.
Fixed Probability Vector
The concept of a fixed probability vector plays a pivotal role in understanding the behavior of Markov chains over the long term. Sometimes referred to as a steady-state vector, this is a vector \(\mathbf{w}\) that remains unchanged when the transition matrix \(\mathbf{P}\) is applied. Mathematically, it satisfies the equation \(\mathbf{w} \mathbf{P} = \mathbf{w}\).
This vector provides insight into the equilibrium distribution of the states, indicating what proportion of time the chain will spend in each state if allowed to run indefinitely.
  • For \(\mathbf{w}\) to be valid, it must meet two criteria:
    • The entries should be non-negative.
    • Their sum must equal 1: \(\sum_i w_i = 1\).
By solving the equation \(\mathbf{w} \mathbf{P} = \mathbf{w}\), one deduces patterns in the chain's transitions, helping to predict long-term performance or results.
Detailed Balance
Detailed balance is a condition often used when working with Markov chains, especially when dealing with their reversibility. To satisfy detailed balance, there should exist a probability vector \(\mathbf{w}\) such that the transition probabilities are balanced in both directions between pairs of states. We can express it mathematically by saying \(w_i p_{ij} = w_j p_{ji}\).
This means for every pair of states \(i\) and \(j\), the weighted flow from \(i\) to \(j\) is the same as the flow from \(j\) back to \(i\). This symmetric relationship is crucial for reversible chains and helps in establishing the fixed probability vector for the reverse transition matrix, \(\mathbf{P}^{*}\).
  • Reversibility: It implies that the chain looks the same if you reverse time.
  • Guarantees that a fixed probability vector for \(\mathbf{P}\) is also valid for \(\mathbf{P}^{*}\).
By ensuring that detailed balance is maintained, one can confirm that both transition matrices share the same fixed probability vector, hence confirming the exercise statement.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume that a man's profession can be classified as professional, skilled laborer, or unskilled laborer. Assume that, of the sons of professional men, 80 percent are professional, 10 percent are skilled laborers, and 10 percent are unskilled laborers. In the case of sons of skilled laborers, 60 percent are skilled laborers, 20 percent are professional, and 20 percent are unskilled. Finally, in the case of unskilled laborers, 50 percent of the sons are unskilled laborers, and 25 percent each are in the other two categories. Assume that every man has at least one son, and form a Markov chain by following the profession of a randomly chosen son of a given family through several generations. Set up the matrix of transition probabilities. Find the probability that a randomly chosen grandson of an unskilled laborer is a professional man.

A study of the strengths of Ivy League football teams shows that if a school has a strong team one year it is equally likely to have a strong team or average team next year; if it has an average team, half the time it is average next year, and if it changes it is just as likely to become strong as weak; if it is weak it has \(2 / 3\) probability of remaining so and \(1 / 3\) of becoming average. (a) A school has a strong team. On the average, how long will it be before it has another strong team? (b) A school has a weak team; how long (on the average) must the alumni wait for a strong team?

Let \(\mathbf{P}\) be a regular transition matrix and let \(\mathbf{w}\) be the unique non-zero fixed vector of \(\mathbf{P}\). Show that no entry of \(\mathbf{w}\) is 0 .

Write a program to simulate the outcomes of a Markov chain after \(n\) steps, given the initial starting state and the transition matrix \(\mathbf{P}\) as data (see Example 11.12). Keep this program for use in later problems.

A process moves on the integers \(1,2,3,4,\) and \(5 .\) It starts at 1 and, on each successive step, moves to an integer greater than its present position, moving with equal probability to each of the remaining larger integers. State five is an absorbing state. Find the expected number of steps to reach state five.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.