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Solve each system of equations using a matrix.

2x+5y=43y-z=34x+3z=-3

Short Answer

Expert verified

The solution for the system of linear equation is-3,2,3.

Step by step solution

01

Step 1. Given information.

Consider the given system of equations,

2x+5y=43y-z=34x+3z=-3

02

Step 2. Write in augmented form.

The augmented matrix for the given system of equations is

250403-13403-3

03

Step 3. Apply row operations.

ApplyR12→R1,

1520203-13403-3

Apply R3-4×R1→R3,

1520203-130-103-11

Apply R23→R2,

1520201-1310-103-11

04

Step 4. Again apply row operations.

Apply R3+10×R2→R3,

1520201-13100-13-1

Apply -3×R3→R3,

1520201-1310013

Now, the matrix is in row-echelon form.

05

Step 5. Write in system of equations. 

Writing the corresponding system of equations,

x+52y=2......(i)y-13z=1......(ii)z=3......(iii)

Substitute z=3in equation (ii),

y-13×3=1y-1=1y=1+1y=2

Substitute y=2in equation (i),

localid="1644429836175" x+52×2=2x=2-5x=-3

06

Step 6. Check the answers.

Substitute the values x,yin equation (i),

-3+522=2-3+5=22=2

This is true.

Substitute the values y,zin equation (ii),

2-133=12-1=11=1

This is also true.

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