/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 218 Solve each system of equations u... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each system of equations using a matrix.

x+2z=04y+3z=-22x-5y=3

Short Answer

Expert verified

The solution for the system of linear equation is4,1,-2.

Step by step solution

01

Step 1. Given information.

Consider the given system of equations,

x+2z=04y+3z=-22x-5y=3

02

Step 2. Write in augmented form.

The augmented matrix for the given system of equations is

1020043-22-503

03

Step 3. Apply row operations.

Apply R3-2×R1→R3,

1020043-20-5-43

Apply R24→R2,

10200134-120-5-43

Apply R3+5×R2→R3,

10200134-1200-1412

Apply -4×R3→R3,

10200134-12001-2

Now, the matrix is in row-echelon form.

04

Step 4. Write in system of equations.

Writing the corresponding system of equations,

x+2z=0......(i)y+34z=-12......(ii)z=-2......(iii)

Substitute z=-2in equation (i),

x+2-2=0x-4=0x=4

Substitute z=-2in equation (ii),

y+34-2=-12y-32=-12y=32-12y=22y=1

05

Step 5. Check the answers.

Substitute the values x,zin equation (i),

4+2-2=04-4=00=0

This is true.

Substitute the values y,zin equation (ii),

1+34-2=-121-32=-12-12=-12

This is also true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.