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91Ó°ÊÓ

In the following exercise, expand the partial sum and find its value

∑k=15k2k−3

Short Answer

Expert verified

Hence,

∑k=15k2k−3=−1−2+9+20+35=61

Step by step solution

01

Step 1. Given information

Thepartialsumisgivenas∑k=15k2k−3Wehavetoexpandandfindthevalueofthepartialsum.

02

Step 2. Expanding the partial sum

⇒∑k=15k2k−3=12⋅1−3+22⋅2−3+32⋅3−3+42⋅4−3+52⋅5−3=12−3+24−3+36−3+48−3+510−3=1−1+2−1+33+45+57=−1−2+9+20+35

03

Step 3. Calculating the sum

Now,

⇒∑k=15k2k−3=−1−2+9+20+35=61

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