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Chapter 12: Q. 269 (page 1218)

Find the eighteenth term of a sequence where the fifth term is 12 and the common difference is seven.

Short Answer

Expert verified

The eighteenth term of a sequence is103

Step by step solution

01

Step 1. Given information

The fifth term of the series is12

The common difference is7

We have to find the 18thterm of the series.

02

Step 2. Find the first term 

We have,

a5=12d=7n=5

Put these values in an=a1+(n-1)d

role="math" localid="1645297666368" 12=a1+(5-1)712=a1+(4)7a1=12-28a1=-16

03

Step 3. Find the term

Put obtained value in an=a1+(n-1)d

a18=-16+(18-1)7a18=-16+(17)7a18=-16+119a18=103

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