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Write the first five terms of the sequence whose general term is an=n!(n+1)!.

Short Answer

Expert verified

The first five terms of the sequence with general term an=n!(n+1)! are12,13,14,15and16.

Step by step solution

01

Step 1. Given information

Thegeneraltermisgivenasan=n!(n+1)!Wehavetowritethefirst5termsofthesequence.

02

Step 2. Calculating the first five terms 

We substitute the values 1, 2, 3, 4, 5 into the formula for the general term.

WeknowIfnisapositiveinteger,then⇒n!=nn−1n−2…

Now,

n=1n=2n=3n=4n=5⇒a1=1!(1+1)!=1!2!=12×1=12⇒a2=2!(2+1)!=2×1!3!=23×2×1=13⇒a3=3!(3+1)!=3!4!=3×2×14×3×2×1=14⇒a4=4!(4+1)!=4!5!=4×3×2×15×4×3×2×1=15⇒a5=5!(5+1)!=5!6!=5×4×3×2×16×5×4×3×2×1=16

03

Step 3. Conclusion

From the above step, we can observe that the first five terms of the sequence will be12,13,14,15and16.

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