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Write the first five terms of the sequence whose general term isan=(n-1)!(n+1)!

Short Answer

Expert verified

The first five terms of the sequence with the general term asan=(n−1)!(n+1)!are12,16,112,120and130.

Step by step solution

01

Step 1. Given information

Thegeneraltermisgivenasan=(n−1)!(n+1)!Wehavetowritethefirst5termsofthesequence.

02

Step 2. Calculating the first five terms 

We substitute the values 1, 2, 3, 4, 5 into the formula an=(n−1)!(n+1)!

WeknowIfnisapositiveinteger,then⇒n!=nn−1n−2…Now,n=1n=2n=3n=4n=5⇒a1=(1−1)!(1+1)!=0!2!=12×1=12⇒a2=(2−1)!(2+1)!=1!3!=13×2×1=16⇒a3=(3−1)!(3+1)!=2!4!=2×14×3×2×1=112⇒a4=(4−1)!(4+1)!=3!5!=3×2×15×4×3×2×1=120⇒a5=(5−1)!(5+1)!=4!6!=4×3×2×16×5×4×3×2×1=130

03

Step 3. Conclusion

From the above step, we can observe that the first five terms of the sequence will be12,16,112,120and130.

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