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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 7: Q. 7.24 (page 650)

Find $R (x) = \frac{f (x)}{g (x)}$ where and $f (x) = \frac{15 x^{2}}{3 x^{2} + 33 x}$ and $g (x) = \frac{5 x - 5}{x^{2} + 9 x - 22} .$

Short Answer

Expert verified

The simplified value of $R (x) = \frac{x (x - 2)}{(x - 1)}$ .

Step by step solution

01

Step 1. Given information

$R (x) = \frac{f (x)}{g (x)}, f (x) = \frac{15 x^{2}}{3 x^{2} + 33 x}, g (x) = \frac{5 x - 5}{x^{2} + 9 x - 22}$

02

Step

$R (x) = \frac{f (x)}{g (x)} R (x) = \frac{\frac{15 x^{2}}{3 x^{2} + 33 x}}{\frac{5 x - 5}{x^{2} + 9 x - 22}} Usegivendata = \frac{15 x^{2}}{3 x^{2} + 33 x} 路 \frac{x^{2} + 9 x - 22}{5 x - 5} Convertdivisionasmultiplication = \frac{5 路 3 路 x 路 x}{3 路 x 路 (x + 11)} 路 \frac{(x + 11) (x - 2)}{5 (x - 1)} Factorize = \frac{5 路 3 路 x 路 x 路 (x + 11) (x - 2)}{5 路 3 路 x 路 (x + 11) (x - 1)} Multiplynumeratoranddenominator = \frac{x (x - 2)}{(x - 1)}$

Hence, $R (x) = \frac{x (x - 2)}{(x - 1)} .$

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Most popular questions from this chapter

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