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Solve by using the Quadratic Formula:5b2+2b+4=0

Short Answer

Expert verified

The solution of the quadratic equation isb=-1±195

Step by step solution

01

Given information

We are given a quadratic equation5b2+2b+4=0

02

Identify the values of x,y,z

On comparing with standard equation we getx=5,y=2,z=4

03

Write quadratic formula and substitute the values of  x,y,z

The quadratic formula can be given as

b=-y±y2-4xz2x

On substituting the values we get

b=-2±4-4(5)(4)2(5)

04

Simplify and also find the common factor and remove it 

On simplifying we get

b=-2±4-8010b=-2±-7610b=-2±76i10

Now we find the common factor and remove it

b=-2±219i10b=2(-1±19i)10b=-1±19i5

05

Rewrite in standard form

We rewrite in standard form

b=-15±195i

06

Conclusion

The solution of the above quadratic equation isb=-15±195i

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