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Solve by using the Quadratic Formula:4a2-2a+8=0

Short Answer

Expert verified

The solution of the quadratic equation isa=1±31i4

Step by step solution

01

Given information

We are given a quadratic equation4a2-2a+8=0

02

Identify the values of a,b,c

On comparing with standard equation we get the values asx=4,y=-2,z=8

03

Write quadratic formula and substitute the values of x,y,z

The quadratic formula can be given as

a=-y±y2-4xz2x

Substituting the values we get

a=2±4-4(4)(8)2(4)

04

Simplify and also find the common factor and remove it

On simplifying we get

a=2±4-1288a=2±-1248a=2±124i8

Now we find and remove the common factor

a=2±231i8a=2(1+31i)8a=1+31i4

05

Rewrite in standard form

It can be written in standard form asa=14±31i4

06

Conclusion

The solution of the above quadratic equation isa=14±31i4

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