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Chapter 9: Q. 249 (page 944)

In the following exercises, find the intercepts of the parabola whose function is given.

f(x)=4x2鈭�20x+25

Short Answer

Expert verified

The x-intercept is 52,0 and the y-intercept are (0,25).

Step by step solution

01

Step 1. Given and explanation  

We are given a function,

f(x)=4x2鈭�20x+25

The y intercept is given by putting x=0 and the x intercept is given by putting the function equals to zero.

02

Step 2. Finding y- intercept 

Putting x=0in the given function, we get

f(0)=4(0)2鈭�20(0)+25f(0)=25

Hence they-intercept is (0,25).

03

Step 3. Finding x- intercept 

Putting f(x)=0, we get

4x2鈭�20x+25=04x2鈭�10x-10x+25=0(2x-5)(2x-5)=02x-5=0x=52

or

2x-5=0x=52

Hence the x-intercept are at the points (52,0).

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