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Chapter 9: Q. 215 (page 920)

A firework rocket is shot upward at a rate of 640 ft/sec. Use the projectile formula h=-16t2+votto determine when the height of the firework rocket will be 1200 feet.

Short Answer

Expert verified

Time will be 38 second and 2 second.

Step by step solution

01

Step 1. Given Information

The initial speed is 640 feet/sec. The height of the rocket is 1200 feet.

02

Step 2. Solving equation

On applying the equation,

h=-16t2+vot

On simplifying,

-16t2+640t=1200-16t2+640t-1200=0t2-40t+75=0a=1,b=-40,c=75t=-b卤b2-4ac2at=-(-40)卤(-40)2-4脳1脳752脳1t=40卤1600-3002t=40卤10132t=20+513=20+18.02鈮�38t=20-513=20-18.02=1.98鈮�2

The time is 38 second and 2 second respectively.

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