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Chapter 3: Q. 3.118 (page 342)

Use the graph of the function to find the indicated values.

Short Answer

Expert verified

(a)f(0)=1(b)f(蟺)=-1(c)f(-蟺)=-1(d)x=-32蟺,-12蟺,12蟺,32蟺(e)x-interceptsare-32蟺,0,-12蟺,0,12蟺,0,32蟺,0(f)y-intercept(0,1)(g)Domain:-2蟺,2蟺(f)Range鈥�:-1,1

Step by step solution

01

Given Information 

The graph of the function

02

Part(a) Step 1: 

When x = 0, the function crosses the y-axis at 0. So, f (0) = 1

03

Part (b) Step 1: 

When x=蟺, the y value of the function is -1

f(蟺)=-1

04

Part(c) Step 1:

When x=-蟺, the y value of the function is -1

f(-蟺)=-1

05

Part(d) Step 1: 

To find out x values when f(x)=0, we look at the points where y=0

x=-32蟺,-12蟺,12蟺,32蟺

06

Part (e) Step 1:

X intercepts occurs when y=0

x intercepts are

-32蟺,0,-12蟺,0,12蟺,0,32蟺,0

07

Part (f) Step 1 :

y intercept is the points that occurs when x=0

y intercept is (0,1)

08

Part(g) Step 1: 

This function has a value when x is from-2蟺to2蟺

Domain in interval notation is[-2蟺,2蟺]

09

Part (h) Step 1: 

This function has y values goes from -1 to 1

Range in interval notation [-1,1]

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