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Chapter 3: Q. 3.117 (page 341)

Use the graph of the function to find the indicated values.

Short Answer

Expert verified

(a) f(0)=0

(b)f12蟺=2

(c)f-32蟺=2

(d)x=-2蟺,-蟺,0,蟺,2蟺

(e) x-intercepts are

(-2蟺,0),(-蟺,0),(0,0),(蟺,0),(2蟺,0)

(f)

y intercept (0,0)

(g) Domain:-2蟺,2蟺

(h)Range[-2,2]

Step by step solution

01

Given information 

Graph is of a function

02

Part (a) Step 1: 

When x = 0, the function crosses the y-axis at 0. So, f (0) = 0.

03

Part (b) Step 1:

When x=12蟺, the y value of the function is 2.

04

Part (c) Step 1:

When x=-32蟺, the y value of the function is 2.

05

Part (d) Step 1:

For x intercept ,

We look at the points where y=0.

The values for x , when f(x)=0 are

x=-2蟺,-蟺,0,蟺,2蟺

06

Part (e) step 1:

x intercepts occurs when y=0

xinterceptsare(-2蟺,0),(-蟺,0),(0,0),(蟺,0),(2蟺,0)

07

Part (f) Step 1: 

y intercept is the points that occurs when x=0.

y intercept is (0,0)

08

Part (g) Step 1: Domain

This function has a value when x is from -2蟺to2蟺

Domain in interval notation is

[-2蟺,2蟺]

09

Part (h) Step 1: Range

This function has y values goes from -2 to 2.

Range in interval notation [-2,2]

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