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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 6: Q 6.31TI (page 582)

Factor completely using trial and error: $8 x^{2} - 13 x + 3$

Short Answer

Expert verified

The trinomial is prime and can't be factored further

Step by step solution

01

Given information

Given the polynomial $8 x^{2} - 13 x + 3$

02

Calculate the factors of the first term

The first term is $8 x^{2}$ the factors are $2 x, 4 x$ so in parentheses, we can write

$(2 x) (4 x)$

03

Factors of the third term

The third term is $3$ so the factors are $1, 3$ and there are no combinations so that it can be factored further

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Most popular questions from this chapter

In the following exercises, factor completely.

${(x + 1)}^{3} + 8 x^{3}$

Factor completely using trial and error: $10 y^{2} - 37 y + 7$

In the following exercises, factor each trinomial of the form $x^{2} + b x + c$ .

$m^{2} - 13 m + 30$

In the following exercises, find the greatest common factor.

$35 x^{3} y^{2}, 10 x^{4} y, 5 x^{5} y^{3}$

In the following exercises, factor.

$鈭� 18 x y^{2} 鈭� 27 x^{2} y$ .

See all solutions

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