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Chapter 6: Q 6.30TI (page 581)

Factor completely using trial and error:4b2+5b+1

Short Answer

Expert verified

The factored form is(4b+1)(b+1)

Step by step solution

01

Given information

Given the polynomial4b2+5b+1

02

Write the factors of the first term 

The first term is 4b2the factors are 4b,1b, putting in parentheses, we get

(4b)(b)

03

Calculating the factors of the third term

The third term is 1, the factors are 1so the combinations are 4,1so we have

(4b+1)(b+1)=4b2+5b+1

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