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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 10: Q. 161 (page 1033)

Evaluate Logarithmic Functions In the following exercises, find the value of $x$ in each logarithmic equation.
$\log_{3} x = - 5$

Short Answer

Expert verified

The value of expression is $x = \frac{1}{243}$

Step by step solution

01

Step 1. Given

An expression is given as $\log_{3} x = - 5$

02

Step 2.Calculation

Change the equation into exponential form as,

$x = (3)^{- 5}$

Simplify,

$x = \frac{1}{(3)^{5}} = \frac{1}{243}$

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Most popular questions from this chapter

In the following exercises, match the graphs to one of the following functions:

$鈸� 2^{x} 鈸� 2^{x + 1} 鈸� 2^{x 鈭� 1} 鈸� 2^{x} + 2 鈸� 2^{x} 鈭� 2 鈸� 3^{x}$

In the following exercises, solve each logarithmic equation.

$\log_{a} 16 = 2$

In the following exercises, solve each logarithmic equation. $y = \log_{1.5} (x)$

On the same coordinate system, graph:

$f (x) = 3^{x}$

$g (x) = 3^{x + 1}$

In the following exercise, find the inverse of each function.

$f (x) = \sqrt[4]{9 x - 5}$

See all solutions

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