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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 10: Q. 160 (page 1033)

Evaluate Logarithmic Functions In the following exercises, find the value of $x$ in each logarithmic equation.
$\log_{2} x = - 6$

Short Answer

Expert verified

The value of expression is $x = \frac{1}{64}$

Step by step solution

01

Step 1. Given

An expression is given as $\log_{2} x = - 6$

02

Step 2. Calculation

Change the equation into exponential form as,

$x = a^{y} x = (2)^{- 6}$

Simplify,

$x = \frac{1}{(2)^{6}} x = \frac{1}{64}$

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Most popular questions from this chapter

In the following exercise, find the inverse of each function.

$x^{3} - 4$

In the following exercises, solve each logarithmic equation, $\log_{a} 81 = 2$

Convert from exponential to logarithmic form:

$e^{x} = 6$ .

In the following exercise, find the inverse of each function.

$f (x) = \sqrt{x - 2}, x 鈮� 2$

In the following exercises, graph each exponential function.

$g (x) = 7^{x}$

See all solutions

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