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Chapter 11: Q. 337 (page 1160)

a) Identify the type of graph of each equation as a circle, parabola, ellipse, or hyperbola, and b) Graph the equation.

x216+y281=1

Short Answer

Expert verified

The graph of the equation is ellipse.

Step by step solution

01

Step 1. Given Information

Given that the equation isx216+y281=1.

02

Step 2. Equation form

The equation looks like the standard form of ellipse. This is an ellipse equation. On converting the given equation in standard form,

x216+y281=1(x-0)242+(y-0)292=1

The center of ellipse is origin (0,0). The length of major and minor axis are 9 units and 4 units respectively.

03

Step 3. Graph of the equation

On drawing the graph,

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